Answer:
P = 2.91*10^{-24} kg m/s
![\lambda = 2.73 *10^{-10} m](https://tex.z-dn.net/?f=%5Clambda%20%3D%202.73%20%2A10%5E%7B-10%7D%20m)
size of atom hat lie in range of 1 to 5 Angstrom
Angstrom
Explanation:
A) MOMENTUM
p = mv
where m is mass of electron
so momentum p can be calculated as
p = 9.11*10^{-31} *3.2*10^{6}
P = 2.91*10^{-24} kg m/s
b) wavelength
![\lambda = \frac{h}{mv}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bh%7D%7Bmv%7D)
where h is plank constant
so![\lambda = \frac{6.626*10^{-34}}{2.91*10^{-24}}](https://tex.z-dn.net/?f=%20%5Clambda%20%3D%20%5Cfrac%7B6.626%2A10%5E%7B-34%7D%7D%7B2.91%2A10%5E%7B-24%7D%7D)
![\lambda = 2.73 *10^{-10} m](https://tex.z-dn.net/?f=%5Clambda%20%3D%202.73%20%2A10%5E%7B-10%7D%20m)
c) size of atom hat lie in range of 1 to 5 Angstrom
d) from the information given in the question we have
![\frac{\Delta v}{v} = 0.1](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20v%7D%7Bv%7D%20%3D%200.1)
![\Delta v = 0.1 v](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%200.1%20v)
we know that
![\Delta p *\Delta x = \frac{h}{4\pi}](https://tex.z-dn.net/?f=%5CDelta%20p%20%2A%5CDelta%20x%20%3D%20%5Cfrac%7Bh%7D%7B4%5Cpi%7D)
![m \Delta v \Delta x =\frac{h}{4\pi}](https://tex.z-dn.net/?f=m%20%5CDelta%20v%20%5CDelta%20x%20%3D%5Cfrac%7Bh%7D%7B4%5Cpi%7D)
![\Delta x = \frac{h}{m \Delta v}](https://tex.z-dn.net/?f=%5CDelta%20x%20%3D%20%5Cfrac%7Bh%7D%7Bm%20%5CDelta%20v%7D)
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Angstrom
The frequency of the wave will not change
I upload the answer via Image because Brainly warned me that there were inappropriate links or words.
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Answer:
the spring coefficient is
k=16N/m
Explanation:
Hooks law states that provided the elasticity of a material is not exceeded the extension e is proportional to the applied force
Step one
Analysis of the problem
From analysis of the problem
The mass has a potential energy due to the height it was dropped from, the potential energy is then stored in the spring since it was dropped on the spring which compresses it by 0.5m
Step two
Data
Mass of object m=0.2kg
Height of building =10m
Compression of spring e=0.5m
Spring constant k=?
Step three
According to the principle of energy conservation
mgh=1/2(k*e^2)
Making k subject of formula we have
k=2mgh/e^2
Substituting our data into the expression to get k
Assuming g=9.81m/s
k=2*0.2*10/0.5^2
k=4/0.25
k=16N/m