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Levart [38]
3 years ago
15

Carbon dioxide: is removed from the atmosphere by photosynthesis. comprises up to two percent of the atmospheric gases. is being

removed from the atmosphere faster than it is being inputted. is not present in significant amounts in the atmosphere of Venus.
Chemistry
1 answer:
raketka [301]3 years ago
3 0

Answer:

Is removed from the atmosphere by photosynthesis.

Explanation:

The carbon dioxide (CO2) is presented in the atmosphere and its cycle began with it's incoming by respiration, combustion of fuels and decomposition. The autotrophs, which realize photosynthesis, use CO2 as fuel to produce their food with Sun rays.

The CO2 comprises about 0.3% of the atmospheric gases, and in the past few years, its input is being higher than its removal of the atmosphere, which is aggravating the greenhouse effect. Besides, the atmosphere of Venus has higher levels of CO2.

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PilotLPTM [1.2K]
1.) homogeneous mixtures

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5 0
3 years ago
1 mole = 1000 millimoles (mmol); 1millimole = 1000 micromoles (µmol). if a solution contains 38231 µmol, what is that amount in
Mrrafil [7]
1 mmol --------------------- 1000 <span>µmol
( mmol ) -------------------- </span> 38231 µmol

mmol =  38231*1 / 1000

mmol = 38231/ 1000

=>  38.231 mmol
3 0
3 years ago
What do you mean by electronegativity ?​
Kamila [148]

Answer:

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Explanation:

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6 0
3 years ago
Read 2 more answers
In a chemical equation, (aq) after one of the substances means that it is which of these? a solid formed from two ionic substanc
Vladimir79 [104]
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3 0
3 years ago
How many grams of ag can be formed from 5.50 grams of ag2o in the equation: 2ag2o (s) → 4ag (s) o2 (g)?
oee [108]

From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.

2Ag₂O(s) → 4Ag (s) + O₂ (g)

We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=\frac{5.50}{231.7}= 0.0237 moles.

From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces \frac{4X0.0237}{2} moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.

Therefore, 5.50 g Ag₂O produces 5.11 g of Ag as per the given balanced chemical reaction.


4 0
3 years ago
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