Ask question

Ask question

All categories

2 years ago

10

What is the third most common gas found in the air we breathe?

2 answers:

Sergio [31]2 years ago

8 0

Argon (Ar) is the third most common gas found in the air we breathe.
Hope this helps~

erastovalidia [21]2 years ago

7 0

Argon is the third most common gas found in the air we breathe. The air we breathe has approximately 78% nitrogen and 21 % oxygen. The third more abundant gas in the air we breathe is Argon. It is available in a very small quantity in the air that we breathe. The percentage of the gas argon is about 0.9% in the air that we breathe. There are several other gases also present in the air that we breathe, but they are found mostly in negligible amounts.

You might be interested in

How many Sodium atoms are in 2.00 mols of Na2O

Anna71 [15]

There’s 1024 atoms of sodium in 2 moles of sodium

7 0

3 years ago

what is the balanced equation for the reaction of solid magnesium metal with oxygen gas to produce solid magnesium oxide

GaryK [48]

Answer:

2Mg + O₂ ⟶ 2MgO

Explanation:

Step 1. Start with the most complicated-looking formula (O₂?).

Put a 1 in front of it.

Mg + 1O₂ ⟶ MgO

Step 2. Balance O.

We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

Mg + 1O₂ ⟶ 2MgO

Step 3. Balance Mg.

We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.

2Mg + 1O₂ ⟶ 2MgO

Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u> <u>On the left</u> <u>On the righ</u>t

Mg 2 2

O 2 2

All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

4 0

2 years ago

What is the total number of joules required to freeze a 10 g sample of water at 0°C?

Lunna [17]

Explanation:

the answer will be 98.4 kJ

8 0

2 years ago

Consider the equation for the formation of water.

Juli2301 [7.4K]

The theoretical yield is 160 g H₂O.

<em>Moles of H₂</em> = 18 g H₂ × (1 mol H₂/2.016 g H₂) = 8.93 mol H₂

<em>Moles of H₂O</em> = 8.93 mol H₂O × (2 mol H₂O/2 mol H₂) = 8.93 mol H₂O

<em>Theoretical yield</em> of H₂O = 8.93 mol H₂O × (18.02 g H₂O/1 mol H₂) = 160 g H₂O

6 0

3 years ago

Describe how oxidation and reduction involve electrons, change oxidation numbers, and combine in oxidation reduction reactions

borishaifa [10]

Answer: Oxidation is defined as the reaction in which there is loss of electrons. It is accompanied by increase in oxidation number.

$Zn\rightarrow Zn^{2+}+2e^{-}$

Zinc in solid state has oxidation number of zero and on losing electrons changes to $Zn^{2+}$ with oxidation number of +2.

Reduction is defined as the reaction in which there is gain of electrons. It is accompanied by decrease in oxidation number.

$2H^++e^{-}\rightarrow H_2$

Hydrogen ions with +1 oxidation state gains electrons and converts to molecular hydrogen with oxidation state of zero.

In the given redox reaction, both oxidation and reduction takes place. They go hand in hand.

$Zn+H_2SO_4\rightarrow ZnSO_4 +H_2$

Zinc converts to $Zn^{2+}$ and gets oxidized. $H^+$ gains electron and convert to $H_2$ .

4 0

2 years ago