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dedylja [7]
3 years ago
6

Two students are working together on a project. One student applies for to a book to move it across the table to the other perso

n. Student 1 applies the force of 20 N to push the book to student 2. If the force of friction resisting is 4, what is the net force acting on the book.
A. 6 N
B. 10 N
C. 24 N
D. 16 N
Chemistry
2 answers:
Bogdan [553]3 years ago
6 0
D 16 N is your answer
Softa [21]3 years ago
3 0

Answer:

D.16 N

Explanation:

20 - 4 = 16

20 N - 4 N = 16 N

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Use the following balanced equation to answer the questions below.
Blababa [14]

Answer:

A. 4.5 mol Mg(OH)₂

B. 6 mol NaOH

Explanation:

Let's consider the following balanced equation.

Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃

PART A

The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:

9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂

PART B

The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:

6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH

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Based on the balanced equation 2C2H2 + 5O2 → 4CO2 + 2H2O calculate the number of excess reagent units remaining when 52 C2H2 mol
erica [24]

Answer:

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2C_2H_2 + 5O_2\rightarrow 4CO_2 + 2H_2O

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As we can see that we have 150 molecules of oxygen gas, but 52 molecules of ethyne will react with 130 molecules of oxygen gas. So, this means that ethyne is a limiting reagent and oxygen gas is an excessive reagent.

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20 molecules of oxygen gas remains after the reaction.

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