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Bogdan [553]
3 years ago
14

Which situation would require the MOST work? A) 20 kg weight lifted 6 m B) 25 kg weight lifted 3 m C) 25 kg weight lifted 6 m D)

50 kg weight lifted 1 m
Physics
1 answer:
Reil [10]3 years ago
5 0

Work= force (N) x distance (m)

F= mass (kg) x acceleration (gravity; m/s^2)

for this question, your formula would be

Work= mass (kg) x acceleration (gravity) x distance (m)

a. F=20kg x 9.81 m/s^2 x6 m = 1177.2 J

b. F=25kg x 9.81 m/s^2 x3 m = 735.75 J

c. F=25kg x 9.81 m/s^2 x6 m = 1471.5 J

d. F=50kg x 9.81 m/s^2 x1 m = 490.5 J


Tip:

  1. If this was a timed test, you could save some time by just multiplying the mass (kg) in the question by the distance because 9.81 is a constant in the formula, you can ignore it (+you're not asked for the final answer). c would still be the largest number
  2. it would also help if you noticed:
  • the distance in c is half that of b but the mass is the same.  eliminate b because c is obviously bigger
  • a and c have the same distance but 25 is greater than 20; eliminate a

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The difference between an electric motor and an electric generator is that a motor converts _______ energy into energy _______,
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Explanation:

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A 12000 kg boat is moving 4.25 m/s. Its engine pushes 9200 N forward, but the current pushes back at 12,500 N. How much times do
Verizon [17]

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15.5 seconds

Explanation:

Apply Newton's second law:

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3 years ago
What is the equivalent resistance of the circuit?
Sonbull [250]

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2 years ago
The electric potential at the origin of an xy-coordinate system is 40 V. A -8.0-μC charge is brought from x = +∞ to that point.
vredina [299]

Answer:

-320 μJ.

Explanation:

Consider a point with an electrical charge of q. Assume that V is the electrical potential at the position of that charge. The electrical potential of that point charge will be equal to:

\text{Potential Energy} = q \cdot V.

Keep in mind that since both q and V might not be positive, the size of the electrical potential energy might not be positive, either.

For this point charge,

  • q = \rm -8.0\; \mu C; (that's -8.0 microjoules, which equals to \rm -8.0\times 10^{-6}\; J)
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Hence its electrical potential energy:

\text{Potential Energy} = q\cdot V = \rm (-8.0\; \mu C) \times 40\; V = -320\; \mu J.

Why is this value negative? The electrical potential energy of a charge is equal to the work needed to bring that charge from infinitely far away all the way to its current position. Also, negative charges are attracted towards regions of high electrical potential. Bringing this \rm -8.0\; \mu C negative charge to the origin will not require any external work. Instead, this process will release 320 μJ of energy. As a result, the electrical potential energy is a negative value.

7 0
3 years ago
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