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Bogdan [553]
3 years ago
14

Which situation would require the MOST work? A) 20 kg weight lifted 6 m B) 25 kg weight lifted 3 m C) 25 kg weight lifted 6 m D)

50 kg weight lifted 1 m
Physics
1 answer:
Reil [10]3 years ago
5 0

Work= force (N) x distance (m)

F= mass (kg) x acceleration (gravity; m/s^2)

for this question, your formula would be

Work= mass (kg) x acceleration (gravity) x distance (m)

a. F=20kg x 9.81 m/s^2 x6 m = 1177.2 J

b. F=25kg x 9.81 m/s^2 x3 m = 735.75 J

c. F=25kg x 9.81 m/s^2 x6 m = 1471.5 J

d. F=50kg x 9.81 m/s^2 x1 m = 490.5 J


Tip:

  1. If this was a timed test, you could save some time by just multiplying the mass (kg) in the question by the distance because 9.81 is a constant in the formula, you can ignore it (+you're not asked for the final answer). c would still be the largest number
  2. it would also help if you noticed:
  • the distance in c is half that of b but the mass is the same.  eliminate b because c is obviously bigger
  • a and c have the same distance but 25 is greater than 20; eliminate a

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8 0
2 years ago
A force vector has a magnitude of 579 newtons and points at an angle 38.0° of below the positive x axis. (a) What is the the x
m_a_m_a [10]

Answer:

a) x- component of force = 432.62 N

b)y- component of force = 338 N

Explanation:

given,

magnitude of force = 549 N

angle between the force vector with positive horizontal x-axis(∅) = 38.0°

a) x-scalar component of the force vector

       x- component of force = F cos ∅

       x- component of force = 549 cos 38°

      x- component of force = 432.62 N

b) y-scalar component of the force vector

       y- component of force = F sin ∅

       y- component of force = 549 sin 38°

      y- component of force = 338 N

8 0
4 years ago
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