Question

A catapult fires a 0.015kg stone at 70m/s.The spring constant of the catapult is 150N/M. Find the exrtention of the catapult.

Answer 1

Answer:

0.495m

Explanation:

The kinetic energy of the stone will be equal to the work done by the spring

Mathematically;

W = KE

1/2ke² = 1/2mv²

ke² = mv²

k is the spring constant = 150N/m

e is the extension

m is the mass = 0.015kg

v is the velocity = 70m/s

Substitute

150e² = 1/2 * 0.015 * 70²

150e² = 36.75

e² = 36.75/150

e² =  0.245

e = √0.245

e = 0.495m

Hence the extension of the catapult is 0.495m