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ivann1987 [24]
3 years ago
7

The overall reaction in the lead storage battery is

Chemistry
2 answers:
Troyanec [42]3 years ago
6 0

Complete Question

The overall reaction in the lead storage battery is

Pb(s) + PbO2(s) + 2H(aq)^+ + 2HSO_4^-(aq) ----> 2PbSO4(s) + 2H2O(l)

Calculate  E at 25°C for this battery when [H2SO4] = 5.0 M; that is, [H + ] = [HSO4− ] = 5.0 M. At 25°C,  E° = 2.04 V for the lead storage battery.

Answer:

The  voltage of the cell is  E  = 2.12V

Explanation:

 From the question we are told that

          The original voltage of the battery is E = 2.04 V

           The concentration of  [H2SO4] = 5.0 M

            The concentration of  [H + ] = [HSO4− ] = 5.0 M

At equilibrium

                   The reaction quotient is  

                                             Q = \frac{1}{[[HSO_4^-]^2 [H^+] ^2]}

Pb(s), Pb(s), 2 H2O(l),2 PbSO4(s) are excluded from the reaction above because they are solid and liquid thus there concentration does not change

                 Q = \frac{1}{5^2 * 5^2}

                    = 1.6*10^{-3}

So the potential for the battery cell is mathematically evaluated as

             E = E^o - \frac{0.05916}{2} log Q

                      =  2.04 - [\frac{0.05916}{2}  log (1.6*10^{-3})]

             E  = 2.12V

                         

Setler [38]3 years ago
5 0

Answer:

2.12 V

Explanation:

see attached file for the detailed step by step solution of the given problem.

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