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rodikova [14]
4 years ago
9

A busy chipmunk runs back and forth along a straight line of acorns that has been set out between its burrow and a nearby tree.

At some instant, it moves with a velocity of −1.09 m/s−1.09 m/s . Then, 2.99 s2.99 s later, it moves with a velocity of 1.75 m/s1.75 m/s . What is the chipmunk's average acceleration during the 2.99 s2.99 s time interval
Physics
1 answer:
Nadusha1986 [10]4 years ago
5 0

Answer:

0.59 seconds

Explanation:

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The laboratory exercise for this chapter addresses kinematic motion. You have experienced these motions in everyday life. Instea
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A) vectors: veloicty, force

scalar:  speed, work

B)  t = 1.75 s,  C)   v = - 17 2 m / s

Explanation:

We answer each part separately

A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude

vector quantities: the speed of a car number is the magnitude and direction is where it goes

Force, the number is the magnitude and above that applies gives direction

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B) I = 15 m height to the soil and get to calculate time = 0

        y = y₀ + v₀ t - ½ g t²

as the ball is loose its initial velocity is zero

       0 = 0 +0  - ½ g t²

       t = \sqrt{2y_o/g}

       t = \sqrt{2 \ 15/ 9.8}

       t = 1.75 s

C) the velocity to the reach the floor

      v = vo - g t

      v = 0 - g t

      v = - 9.8 1.74

       v = - 17 2 m / s

The negative signt iindicates that the speed goes down

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