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olchik [2.2K]
3 years ago
5

A student placed a pencil in a cup of water. The pencil appears broken because light- always travels in a straight line makes th

e water in the glass evaporate bends when it passes through water reflects the pencil on the water's surface
Physics
2 answers:
antiseptic1488 [7]3 years ago
6 0

Answer : The pencil appears broken because it bends when it passes through water.

Explanation :

When a student placed a pencil in a cup of water, the pencil appears broken. This is due to the refraction of light.

The bending of light when it moves from one medium to another is called refraction of light. When the light travels from denser to rarer medium, it gets bends away from the normal.

While when the light travels from rarer to a denser medium, it moves towards the normal.

So, the correct option is " bends when it passes through water ".

il63 [147K]3 years ago
5 0
<span>None of the choices makes a correct statement.  The third choice is close,
but misleading.

The pencil appears broken because light bends away from a straight line
when it crosses the boundary between air and water.</span>
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<span>The word is "pitch", which is exactly that: How "high" or "low" a sound is.</span>
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4 years ago
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What distance will a car traveling at a speed of 15 m/s cover in 300 s?
AnnZ [28]

Distance formula: d = st

d = 15 * 300

d = 4,500m

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3 years ago
Consider the power dissipated in a series R–L–C circuit with R=280Ω, L=100mH, C=0.800μF, V=50V, and ω=10500rad/s. The current an
ki77a [65]

Answer:

0.28802

2.57162 W

14.28 W

53.55 W

6.07142 W

Explanation:

R = 280Ω

L = 100 mH

C = 0.800 μF

V = 50 V

ω = 10500rad/s

For RLC circuit impedance is given by

Z=\sqrt{R^2+(X_L-X_C)^2}\\\Rightarrow Z=\sqrt{R^2+(\omega L-\dfrac{1}{\omega C})^2}\\\Rightarrow Z=\sqrt{280^2+(10500\times 100\times 10^{-3}-\dfrac{1}{10500\times 0.8\times 10^{-6}})^2}\\\Rightarrow Z=972.1483\ \Omega

Power factor is given by

F=\dfrac{R}{Z}\\\Rightarrow F=\dfrac{280}{972.1483}\\\Rightarrow F=0.28802

The power factor is 0.28802

The average power to the circuit is given by

P=\dfrac{V^2}{Z}\\\Rightarrow P=\dfrac{50^2}{972.1483}\\\Rightarrow P=2.57162\ W

The average power to the circuit is 2.57162 W

Power to resistor

P_R=IR\\\Rightarrow P_R=5.1\times 10^{-2}\times 280\\\Rightarrow P_R=14.28\ W

Power to resistor is 14.28 W

Power to inductor

P_L=IX_L\\\Rightarrow P_L=5.1\times 10^{-2}\times 10500\times 100\times 10^{-3}\\\Rightarrow P_L=53.55\ W

Power to the inductor is 53.55 W

Power to the capacitor

P_C=IX_C\\\Rightarrow P_C=5.1\times 10^{-2}\times \dfrac{1}{10500\times 0.8\times 10^{-6}}\\\Rightarrow P_C=6.07142\ W

The power to the capacitor is 6.07142 W

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The CORRECT answer would be false. They are different and so therefore the answer is false.

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