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Black_prince [1.1K]
3 years ago
14

Match the vocabulary terms to their definitions.

Chemistry
1 answer:
mariarad [96]3 years ago
8 0

Answer:

Units Accuracy = the degree to which a measurement can be

Column Matter = anything that has mass and occupies

Space Precision = an indication of how close a measurement is to the correct

Replicated Meniscus = the curved top surface of a liquid

Result Density = the mass of an object per unit volume

Volume = space occupied, measured in cubic

Explanation:

In the fields of science , the Unit Accuracy of a measurement system is the degree of closeness of measurements of a quantity to that quantity's true value.

Column Matter can be defined as anything that had mass and occupies space.

Space Precision refers to the closeness of the measurements to each other. It's the quality, condition, or fact of being exact and accurate.

Replicated Meniscus is the curve in the upper surface of a liquid close to the surface of the container or another object, caused by surface tension. It can be either concave or convex, depending on the liquid and the surface.

Result Density can be defined as the mass of an object per unit volume.

Volume: The space occupied by any object is called the volume. The volume of an object is the amount of space occupied by the object. Volume is measured in "cubic units".

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Answer:

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Explanation:

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Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe
leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as <u>molarity</u>, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

c = \frac{n}{V}

n = moles (unit mol)

V = volume (unit L)

<u>Find the molar mass (M) of potassium hydroxide.</u>

M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}

M_{KOH} = 56.106 \frac{g}{mol}

<u>Calculate the moles of potassium hydroxide.</u>

n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}

n_{KOH} = 0.25941(9)mol

Carry one insignificant figure (shown in brackets).

<u>Convert the volume of water to litres.</u>

V = \frac{500.0mL}{1}*\frac{1L}{1000mL}

V = 0.5000L

Here, carrying an insignificant figure doesn't change the value.

<u>Calculate the concentration.</u>

c = \frac{n}{V}

c = \frac{0.25941(9)mol}{0.5000 L}              

c = 0.5188(3) \frac{mol}{L}         <= Keep an insignificant figure for rounding

c = 0.5188 \frac{mol}{L}              <= Rounded up

c = 0.5188M               <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

7 0
3 years ago
A gas that exerts a pressure of ? bar in a container with a volume of 0.5650 L will exert a pressure of 715.1 bar when transferr
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PV(before) = PV(after)

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What is the main benefit of this model?
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Answer:

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Explanation:

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