The collective name for the abiotic factors which include light, temperature, water, atmospheric gases and wind.

What is the resulting formula unit when magnesium and nitrogen bond

muminat

The answer is Mg3N2.

5 0

3 years ago

Mendeléyev diseño su tabla casi al mismo tiempo que un químico alemán llamado Julius Lothar Meyer, quien la publicó un año despu

lord [1]

Answer:

Mendeléyev designed his table around the same time as a German chemist named Julius Lothar Meyer, who published it a year later. However, finally Mendeléyev's order was imposed. Do you know what his great success was? Help plis.

Mendeleev predicted the existence and properties of unknown elements that he called eka-aluminum, eka-boron, and eka-silicon, his table is based on atomic weight.

Explanation:

Gallium, scandium, and germanium were later discovered to coincide with his predictions. In addition to the fact that Mendeleev's table was published before Meyers, his work was more extensive, predicting the existence of other elements not known at the time.

4 0

3 years ago

PLEASE HELP! 25 POINTS!!!! I got the #1, just not #2 and #3. An industrial chemical company has opened a new plant that will pro

podryga [215]

Answer :

Part 1 : Balanced reaction, $3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

Part 2 : The theoretical yield of $NH_3$ gas = 440.96 g

Part 3 : The % yield of ammonia is 90.03 %

Solution : Given,

Mass of $N_2$ = 475 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $NH_3$ = 17 g/mole

Experimental yield of $NH_3$ = 397 g

<u>Answer for Part (1) :</u>

The balanced chemical reaction is,

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

<u>Answer for Part (2) :</u>

First we have to calculate the moles of $N_2$ .

$\text{Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molecular mass of }N_2}=\frac{475g}{28g/mole}=16.96moles$

From the given reaction, we conclude that

1 moles of $N_2$ gas react to give 2 moles of $NH_3$ gas

16.96 moles of $N_2$ gas react to give $\frac{2}{1}\times 16.96=33.92$ moles of $NH_3$ gas

Now we have to calculate the mass of $NH_3$ gas.

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(33.92moles)\times (17g/mole)=440.96g$

Therefore, the theoretical yield of $NH_3$ gas = 440.96 g

<u>Answer for Part (3) :</u>

Formula used for percent yield :

$\% \text{ yield of }NH_3=\frac{\text{ Experimental yield of }NH_3}{\text{ Theoretical yield of }NH_3}\times 100$

$\% \text{ yield of }NH_3=\frac{397g}{440.96g}\times 100=90.03\%$

Therefore, the % yield of ammonia is 90.03 %

3 0

3 years ago

What is the name of the isotope produced when Californium-251 emits an alpha particle?

Charra [1.4K]

<h3>Answer:</h3>

Curium-247 <em>i.e.</em> ²⁴⁷₉₆Cm

<h3>Explanation:</h3>

Alpha decay is given by following general equation,

ᵃₓA → ⁴₂He + ᵃ⁻⁴ₓ₋₂B

Where;

A = Parent Isotope

B = Daughter Isotope

ᵃ = Mass Number

ₓ = Atomic Number

Californium-251 is the parent isotope in our case and it has 98 protons (atomic number) and is given as,

²⁵¹₉₈Cf

The alpha decay reaction of Californium-251 will be as,

²⁵¹₉₈Cf → ⁴₂He + ²⁴⁷₉₆B

The symbol for B with atomic number 96 was found to be the atom of Curium (Cm) by inspecting periodic table. Hence, the final equation is as follow,

²⁵¹₉₈Cf → ⁴₂He + ²⁴⁷₉₆Cm

3 0

3 years ago

Which one of the following is an incorrect orbital notation?

Alexxx [7]

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

4 0

3 years ago

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The collective name for the abiotic factors which include light, temperature, water, atmospheric gases and wind.​

The collective name for the abiotic factors which include light, temperature, water, atmospheric gases and wind.