1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olenka [21]
3 years ago
15

A plot of binding energy per nucleon Eb A versus the mass number (A) shows that nuclei with a small mass number have a small bin

ding energy per nucleon, as the mass number increases the binding energy per nucleon increases, and the value for the binding energy per nucleon has a maximum value for nuclei with a mass number around 60. Verify that this is the case by determining the binding energy per nucleon for each of the following four nuclei. (Let the mass of a proton be 1.0078 u, the mass of a neutron be 1.0087 u, the mass of 6He be 6.0189 u, the mass of 8Li be 8.0225 u, the mass of 62Ni be 61.9283 u, and the mass of 115In be 114.9039 u. Enter your answers in MeV and to at least three significant figures.) (a) 6He MeV (b) 8Li MeV (c) 62Ni MeV (d) 115In MeV
Chemistry
1 answer:
Illusion [34]3 years ago
8 0

Answer:

6He =   4.90 MeV/Nucleon

8Li =     5.18  MeV / Nucleon

62Ni =   8.82 MeV / Nucleon

115 In =  8.54 MeV / Nucleon

Explanation:

Our strategy here is to remember that when the mass of a given nuclei is calculated from the sum of the mass of its  protons and neutrons, this mass is greater than  the actual  value . This is the mass defect.

Now this mass defect we can convert to energy  by utilizing Einstein´s equation, E = mc².This is  the binding energy.

For 6He with actual mass 6.0189 u ( He has Z = 2, that is 2 protons )

mass protons =   2 x 1.0078 u  =  2.0516 u

mass neutrons = 4 x 1.0087 u  =  4.0348 u

predicted mass = (2.0516 + 4.0348) u = 6.0504 u

mass defect = (6.0504 - 6.0189) u = 0.0315 u

Now we need to convert this mass expressed in atomic mass units to kilograms ( 1 u = 1.66054 x 10⁻²⁷ Kg )

0.0315 u x 1.66054 x 10⁻²⁷ Kg =5.231 x 10⁻²⁹ Kg

E =5.231x 10⁻²⁸ Kg x (3 x 10⁸ m/s )² = 4.707 x 10⁻¹²J

Finally we will convert this energy in Joules to eV

E = 4.707 x 10⁻¹²  J x 6.242 x 10¹⁸ eV/J = 2.94 x 10⁷ eV = 29.4 MeV

E per nucleon for 6He = 29.4 MeV / 6 =4.90 MeV / Nucleon

Now the calculations for the rest of the nuclei are performed in similar manner with the following results:

8Li = 5.18 MeV / Nucleon

62Ni = 8.82 MeV / Nucleon

115 In =  8.54 MeV / Nucleon

You might be interested in
Given the molar specific heat cv of a gas at constant volume, you can determine the number of degrees of freedom s that are ener
Ksju [112]
The molar specific heat Cv = R s / 2
70.6 J/mol.K = (8.314 J/mol.K) * s / 2
So the number of degrees of freedom are:
s = 16.98 = 17
8 0
3 years ago
Read 2 more answers
Draw an ether that contains exactly five carbon atoms and only single bonds
Eddi Din [679]

<em>Answer:</em>

  •                                       H3CH2COCH2CH2CH3

<em>Ether:</em>

Ether are organic compounds that contain ether functional group , in which oxygen atom is connected with two alkyl or aryl group.

They have general formula as follow

  • R---O---R   or R'---O----R or R'---O---R'

            while  R = Alkyl

                       R' = Aryl

8 0
3 years ago
HELPPP simply the expression!!!!
coldgirl [10]

Answer:

\frac{3}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }  =  \frac{3 \sqrt{3} }{3}  =  \sqrt{3}

when there is a radical in the denominator, we should rationalize (mutiply the denominator and numerator by the radical) to get rid of the radical in the denominator.

4 0
2 years ago
What is the name of the people who hid the Dead Seas Scrolls. When did they live at Qumran?
Shkiper50 [21]
It was named the Qumran seas scrolls.
3 0
3 years ago
6. How is energy transferred to the earth?I
qaws [65]

Answer:

Energy is transferred between the earths surface and atmosphere.Energy move place to place

8 0
3 years ago
Other questions:
  • Help please I don’t know the answer
    14·2 answers
  • Which must be a mixture of substances?<br> (1) solid (3) gas<br> (2) liquid (4) solution
    10·1 answer
  • Which of the following represents the mass of an oxygen molecule?
    8·1 answer
  • Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press
    6·1 answer
  • A piece of aluminum has a mass of 12.0 g. When it is placed into a graduated
    11·1 answer
  • Fill in the blanks for
    11·2 answers
  • a 3.81 g sample of NaHCO3 was completely decomposed. After decomposition, Na2CO3 had mass of 2.86g. Determine mass of H2CO3 prod
    8·1 answer
  • Which statement does NOT correctly compare boron with another element?
    9·1 answer
  • If a 12oz can of Soda contains 48.0g of sugar and you drink one can a day for one month (31 days), how many pounds (lb) of sugar
    5·1 answer
  • Where are these chemical reactions happening?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!