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cluponka [151]
3 years ago
12

Please Help! Check the following problem for errors. If you find an error, identify it, tell why it is an error and correct the

error solving the problem correctly. Convert 0.45 g zinc hydroxide to moles. (Hint: there are errors)
0.65 g ZnOH 82.41 mol = 3.22 X 10 25 mol
6.02X1023 g
Chemistry
1 answer:
Wewaii [24]3 years ago
4 0
The question says only to convert the Zn(OH)₂ into moles. But the given answer has many errors such as formula, mass and moles.

<span>The corrected answer is as follows.

</span>Moles (mol) = mass (g) / molar mass (g/mol)
<span>
</span>
<span>Mass of Zn(OH)₂</span><span> = 0.45 g
Molar mass of Zn(OH)₂ = </span><span>99.424 g/mol
</span>Hence, moles of Zn(OH)₂ = 0.45 g / 99.424 g/mol
<span>                                         = 4.526 x 10⁻³ mol


</span>
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Common salt besides being used in kitchen can also be used as the raw material for making.
Anon25 [30]

Common salt besides being used in kitchen can also be used as the raw material for making washing soda and baking soda.

The overall balanced reaction for washing soda preparation:

2NaCl + CaCO3 → Na2CO3 + CaCl2

NaCl is sodium chloride or common salt

Na2CO3 is sodium carbonate or washing soda

CaCO3 is calcium carbonate or limestone

The overall balanced reaction for baking soda preparation:

NaCl + CO2 + NH3 + H2O → NaHCO3 + NH4Cl

Baking soda (NaHCO₃ - sodium bicarbonate) is white, solid, crystalline salt or appears as a fine powder.

NH3 is ammonia

CO2 is carbon (II) oxide

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3 0
1 year ago
Part of molten rock at mid-ocean ridges
erastovalidia [21]

Answer:

Magma

Explanation:

Magma is part of molten rock at mid-ocean ridges.

Hope this helps!

4 0
3 years ago
Molecular formula of sodium sulphate from Criss cross method​
uranmaximum [27]

Answer:

Na2SO4

Explanation:

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For sodium sulphate;

Na ^+        SO4^2-

By crisscrossing and dropping the signs to obtain the subscripts we now have;

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5 0
3 years ago
When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and
AysviL [449]

9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

Oxygen produced - 1.618 gram

Decomposition of N_2O_5 takes place.

Find - Amount of NO_2 produced.

The decomposition reaction is as follows -

2N_2O_5--> 4NO_2 + O_2

Moles of O_2 gas =\frac{1.6}{16}  =0.1 moles.

1 mole of O_2 is produced from 2 moles of dinitrogen pentoxide

0.1 mole of O_2  will be produced from = 0.2 moles.

Now, 2 moles of dinitrogen pentoxide produce 4 moles of NO_2

NO_2 produced will be - 0.4 moles.

Weight of NO_2 produced - 0.4 X 46

Weight of NO_2  produced - 18.4 gram

Thus, grams of NO_2 produced are 18.4

Now calculate the volume of NO_2

Given data are:

P=103.25 kPa =1.01899827 atm

T= 22.75 °C +273 = 295.75 K

n=0.4 moles

V=?

R= 0.0821 liter·atm/mol·K

Putting the value in PV=nRT

V =  \frac{nRT}{P}

V =  \frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}

V= 9.5314 L

Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

Learn more about the ideal gas equation here:

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8 0
2 years ago
a student is asked to prepare 75.0 ml of a 130M solution of HF using a 2.000M standard solution. Calculate the volume in mL of 2
Blizzard [7]

Answer:

Volume required from standard solution = 4675 mL

Explanation:

Given data:

Final volume = 75.0 mL

Final molarity = 130 M

Molarity of standard solution = 2.000 M

Volume required from standard solution = ?

Solution:

We use the formula,

C₁V₁ = C₂V₂

here,

C₁ = Molarity of standard solution

V₁ = Volume required from standard solution

C₂ = Final molarity

V₂ = Final volume

Now we will put the values in formula,

C₁V₁ = C₂V₂

2.000 M × V₁ = 130 M × 75.0 mL

V₁  = 9750 M. mL / 2.000 M

V₁  = 4675 mL

5 0
4 years ago
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