Answer:
Number of bacteria after 100 days is 1237.
Step-by-step explanation:
Since bacterial growth is a geometrical sequence.
Therefore, their population after time t will be represented by the expression

Where a = first term of the sequence
r = common ratio of the sequence
n = duration or time
Since first term of the sequence = number of bacteria in the start = 1
Common ratio = r = (1 + 0.04) = 1.04
![S_{100}=\frac{1[(1.04)^{100}-1)]}{1.04-1}](https://tex.z-dn.net/?f=S_%7B100%7D%3D%5Cfrac%7B1%5B%281.04%29%5E%7B100%7D-1%29%5D%7D%7B1.04-1%7D)
= 
= 1237.64 ≈ 1237 [Since bacteria can't be in fractions]
Therefore, number of bacteria after 100 days is 1237.
sqr of 4^2 would be something like 4
Hello! Congruent figures are those with the same size and shape. With that being said, if you look at the shapes correctly, here are your answers:
Quad 1 & 2: Not Congruent
Quad 1 & 3: Congruent
Quad 1 & 4: Congruent
Quad 2 & 3: Not Congruent
Quad 2 & 4: Not Congruent
Quad 3 & 4: Congruent
Answer:
<h2>A. x ≤2 or x>6</h2>
Step-by-step explanation:
2x+6 ≤ 10 or 2x + 8 > 20
⇔ 2x ≤ 4 or 2x > 12
⇔ x ≤ 2 or x > 6