Equivalent fractions are always larger than orginal fraction true or false?

Mathematics

1 answer:

ioda3 years ago

8 0

The answer is false. They are the same

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The sum of two numbers is 62, and their difference is 8. What are the numbers

Lemur [1.5K]

Sum of two numbers is 62?
Let's call the two numbers $a$ and $b$

let's find two same numbers that would add up to 62: 31.
31 + 31 = 62

since it said the difference is 8, we have to add 4 to one number and subtract 4 from another.
31 - 4 = 27
31 + 4 = 35

Therefore, the two numbers following the given rules are 27 and 35

7 0

3 years ago

C(1)=−20 c(n)=c(n−1)+10 Find the second term in the sequence.

svet-max [94.6K]

Answer:

c(2) = -10

Step-by-step explanation:

The first equation says that the first term of the sequence is -20.

The second equation is saying that to find any term of the sequence, add 10 to the previous term.

c(2) = c(2-1) + 10

c(2) = c(1) + 10

c(2) = -20 + 10 = -10

5 0

2 years ago

Simplify by combining like terms 7x + 3 (2x-6) - 10 - 7x

ruslelena [56]

6x-28 is what I got for this

3 0

2 years ago

Read 2 more answers

Drag values to complete each equation.

Alex777 [14]

Answer:

1. A. 1

2. D. $17^9$

Step-by-step explanation:

Properties used:

Power of a Power Property
Product Property
Quotient Property
Zero Exponent Property

1. First, let's deal with the numerator.

$(17^3)^6$ can be turned into $17^1^8$ by using the Power of a Power Property.

And then use the Product Property, $(17^1^8)(17^-^1^0) = 17^8$

So now, our fraction is this: $\frac{17^8}{17^8}$

All number over itself in a fraction is equal to 1. But you can also do this the mathmatic way using the Quotient Property: $\frac{a^m}{a^n} = a^m^-^n$ or $\frac{1}{a^(^n^-^m^)}$ . Which then you plug the numbers in: $\frac{17^8}{17^8} = 17^8^-^8 = 17^0$ . And since we know that in Zero Exponent Property: $a^0 = 1$ , we can see that $17^0 = 1$ . So either way, we get 1.