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RSB [31]
3 years ago
12

At 20 degrees Celsius, the density of air is 1.20 g/L. Nitrogen's density is 1.17 g/L. Oxygen's density is 1.33 g/L. Will balloo

ns filled with oxygen rise or sink in the air? Will balloons filled with nitrogen rise or sink in the air? Why? (3 points)
Chemistry
2 answers:
Anna [14]3 years ago
3 0
Balloons filled with oxygen will sink and balloons filled with nitrogen will also sink, this is because oxygen is more dense than air but nitrogen is only slightly less dense than air meaning it is not enough for the nitrogen to rise
Anna007 [38]3 years ago
3 0

Answer : When the balloons filled with oxygen then the balloons will sink.

When the balloons filled with nitrogen then the balloons will float.

Explanation :

As we given that:

The density of air = 1.20 g/L

The density of nitrogen = 1.17 g/L

The density of oxygen = 1.33 g/L

  • When the density of a substance will be greater than the density of medium then the substance will sink.
  • When the density of a substance will be lesser than the density of medium then the substance will float.

Here, substance is nitrogen and oxygen and medium is air.

As per question we conclude that,

The density of substance (oxygen) is greater than the density of medium (air). That means, when the balloons filled with oxygen then the balloons will sink.

The density of substance (nitrogen) is less than the density of medium (air). That means, when the balloons filled with nitrogen then the balloons will float.

Hence, the correct option is, It would float.

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An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the
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The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

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Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

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The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

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rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

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