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DENIUS [597]
3 years ago
10

Devices that allow for the retention of data when your computer has been shutdown

Computers and Technology
1 answer:
zepelin [54]3 years ago
4 0
That would be persistent storage devices (non-volatile memory)
- hard disk drives (mechanical)
- solid state drives (electronic / NAND flash)
- CD (optical)

If u need more I can give u a few more
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In symmetric encryption the same key is used to encrypt and decrypt a message. in asymmetric encryption different keys are used
Brrunno [24]

A useful advantage of Asymmetric encryption over symmetric encryption is that there is no secret channel necessary for the exchange of the public key, unlike in the symmetric encryption which requires a secret channel to send the secret key.  

Another advantage of Asymmetric encryption is that is has increased security. Asymmetric uses two different keys (Public and private) for both encryption and decryption of data while symmetric uses one.

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3 years ago
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During data declaration, a name is binded to a memory location, what else can be identify as part of this process?
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example:

int r;

char name;

float g;

double k= 23.34;

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3 years ago
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A place to watch daisy Taylor vids
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Where are methods listed in a UML class diagram showing three parts?
denis23 [38]

Answer:

the bottom third

Explanation:

Check out the exampe below.

swim() would be an example of a method.

3 0
2 years ago
Allocate 100 integers and assign the resulting pointers to the elements of ip_arr. Initialize each integer value to -1.
dmitriy555 [2]

Answer:

#include <iostream>

using namespace std;

int main() {

   int *ip_arr,n;//pointer name inp_arr and integer n to store the size.

   cin>>n;//size.

   for(int  i=0;i<n;i++)

   ip_arr[i]=-1;//assigning -1 to every element.

  for(int i=0;i<n;i++)

  {

       cout<<ip_arr[i]<<" ";//printing every element.

  }

return 0;

}

output:-

100

-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1  

Explanation:

I am taking input of size.You should enter 100 for 100 values which have value -1.

5 0
3 years ago
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