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Julli [10]
3 years ago
15

An atom’s mass number equals the number of

Physics
2 answers:
steposvetlana [31]3 years ago
8 0
An atom's mass number equals the number of protons plus the number of neutrons.
Hope this helps! (:
oksian1 [2.3K]3 years ago
4 0

b.  protons plus the number of neutrons.

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A high-speed train travels 480 km from Paris to Grenoble, France, at an average speed of 180 km/h. How long will it take to reac
hichkok12 [17]
The time (t) it will take for the train to reach to Grenoble is the quotient when the distance (d) is divided by the speed (s). That is,
                                       t = d / s
Substituting the known values,
                                       t = 480 km / 180 km/h
                                      t = 2.667 h
Thus, it will take approximately 2.7 h to reach Grenoble. The answer is letter D. 
7 0
3 years ago
The drawing shows a model for the motion of the human forearm in throwing a dart. Because of the force M applied by the triceps
Serga [27]

Answer:

464.3 N

Explanation:

Given parameters are:

I = 0.065 kg*m^2

L = 0.025 m

R = 0.28 m

v_0 = 0 m/s

v_f = 5 m/s

t = 0.1 s

v_f=v_0+at=at

Hence, a=v_f/t

We must connect two torque equations to find the answer.

\tau=LM=I\alpha

Where \alpha =\frac{a}{R} =\frac{v_f}{Rt}

Hence, LM=I\frac{v_f}{Rt}

Thus, M = \frac{Iv_f}{LRt} = \frac{0.065*5}{0.025*0.28*0.1} =464.3 N

5 0
4 years ago
Which is best supported by the data in the chart? Current W flows at a higher rate than Current Z. Current Y flows at a lower ra
LekaFEV [45]
There is no chart provided in this statement. However, the current that flows within an electrically charged item is dependent on how it is arranged. There are two kinds of current and these are, parallel and circuit currents. Current that flows in  parallel current is less than when it is farther away from the electric source; current that flows in a series current flows at a constant rate regardless of how far it is from the electrical source.
7 0
3 years ago
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A girl who is watching a plane fly tells her friend that the plane isn't moving at all. Describe a frame of reference in which t
Dafna1 [17]
If the plane is far away and flying directly toward or away from
the girl, the plane would appear not to be moving. Also, the plane
would not be moving in the frame of reference of the people on
the plane. If you are matching speed and direction of the plane.
6 0
3 years ago
Read 2 more answers
Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that th
lozanna [386]

Answer:

Part a)

Velocity of sled

v = \frac{m_1 s}{m_1 + m_2 + M}

velocity of first man who jump off

v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}

Part b)

Velocity of sled

v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s

Also the speed of second person is given as

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}

Part c)

change in kinetic energy of sled + two people is given as

KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

Explanation:

As we know that here we we consider both people + sled as a system then there is no external force on it

So here we can use momentum conservation

since both people + sled is at rest initially so initial total momentum is zero

now when first people will jump with relative velocity "s" then let say the sled + other people will move off with speed v

so by momentum conservation we have

0 = m_1(v - s) + (m_2 + M)v

v = \frac{m_1 s}{m_1 + m_2 + M}

so velocity of the sled + other person is

v = \frac{m_1 s}{m_1 + m_2 + M}

velocity of first man who jump off

v_1 = \frac{m_1 s}{m_1 + m_2 + M} - s

v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}

Part b)

now when other man also jump off with same relative velocity

so let say the sled is now moving with speed vf

so by momentum conservation we have

(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) = m_2(v_f - s) + Mv_f

(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) + m_2s = (m_2 + M)v_f

Now we have

v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s

Also the speed of second person is given as

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s - s

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}

Part c)

change in kinetic energy of sled + two people is given as

KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

here we know all values of speed as we found it in part a) and part b)

4 0
3 years ago
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