Momentum equation is
change in momentum = mass•initial velocity•final velocity
so....
p=700(15) because your initial is 30, and your final in 15, so you subtract! hope that helped!
C. Forces are always in pairs
Aswer:
False, the values of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.
Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.
<u>xXCherryCakeXx</u>.
Answer:
PLEASE MARK ME BRAINLIEST!!!
Explanation:
Given initial velocity of ambulance
v0=18m/s , acceleration a=5m/s2
To find distance, x=?
First we need to calculate the time for which it acquires 30\,m/s. For that use equation
v=v0+at
30=18+5×t
⇒t=30−185=125seconds
Distance travelled by the ambulance
x=v0t+12at2
x=(18×125)+12×5×(125)2
x=43.2+2.5×5.76=43.2+14.4
x=57.6m
Therefore the ambulance has to travel 57.6 m to match the velocity of car.
Answer:
See the answers and explanation below
Explanation:
To solve this problem, we must have the full description of this problem, by doing an internet search we can find a problem with the same description and with the respective question.
<u>Description of the problem</u>
<u />
"Vertically oriented circular disks have strings wrapped around them. The other ends of the strings are attached to hanging masses. The diameters of the disks, the masses of the disks, and the masses of the hanging masses are
given. The disks are fixed and are not free to rotate. Specific values of the variables are given in the figures. Rank these situations, from greatest to least, on the basis of the magnitude of the torque on the disks. That is, put first the situation where the disk has the greatest torque acting on it and put last the situation where the disk has the least torque acting on it."
<u>For case D</u>
<u />
T = (20/2)*800 = 8000 [g-cm]
<u>For case A</u>
<u />
T = (20/2)*500 = 5000 [g-cm]
<u>For case C</u>
<u />
T = (10/2)*500 = 2500 [g-cm]
<u>For case B</u>
<u />
T = (10/2)*200 = 1000 [g-cm]
In this way it has been organized from the largest to the smallest torque present in each of the cases.
