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rusak2 [61]
3 years ago
12

You place a book on top of a spring and push down, compressing the spring by 10 cm. When you let go of the book, it is pushed up

by the spring. Which statement describes what happens to the energy of the spring-book-system?
Physics
2 answers:
enot [183]3 years ago
4 0
At First, there is chemical Energy( in your muscels) which is Used to Push down the spring. This Energy becomes the Energy of the spring, which increases until you stop pushing. If you Put your hand away, the Energy of the spring will become kinetic energ. This Energy is at the highest Level the Moment the book ist Leaving the spring. Afterwards, the kinetic Energy decreases while the Gravitational Potential Energy increases.
DochEvi [55]3 years ago
3 0

Answer: The gravitational potential energy of the system increases.

Explanation:

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Answer:

Magnetic compass

Explanation:

A magnetic field is a field that describes the magnetic effect of electric charges in a relative motion.

Magnetic field allows magnets to interact without contact. The principle involved in the function of the compass is that a magnetic field exerts a force on any moving charge and can be measured and detected by this effect.

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Hunter wants to measure the weight of a dumbbell. He should
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Use a scale and record the weight in cm^3
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Solve this questions please ​
Rudik [331]

Answer:

10.37×10³j

Explanation:

hope this helps you !!!

4 0
3 years ago
The cable of a crane is lifting a 950 kg girder. The girder increases its speed from 0.25 m/s to 0.75 m/sin a distance of 5.5m
Umnica [9.8K]

Explanation:

a) How much work is done by gravity?

  • w = f x d
  • w = 950 x 10 x 5.5 = 52250j

b) How much work is done by tension?

  • v²=u²+2as
  • 0.75²=0.25²+2a x5.5
  • 0.56=0.06+2a x5.5
  • 2a x5.5 = 0.56 - 0.06
  • 2a x 5.5 =0.5
  • 11a=0.5
  • a = 0.5/11 = 0.05m/s²

w = f x d

w = 950 x 0.05 x 5.5 = 261.25j

7 0
3 years ago
Determine the amount of work done by the engine of a car with a mass of 2500 kg when it accelerates from 45 mph to 65 mph. (Use
Y_Kistochka [10]

Answer:

amount of work done, W = 549.36 kJ

Given:

mass of a car engine, m = 2500 kg

initial velocity, u = 45 mph

final velocity, v = 65 mph

1 mile = 1609

Solution:

We know that 1 hour = 3600 s

Now, velocities in m/s are given as:

u = 45 mph = \frac{45\times 1609}{3600} = 20.11 m/s

v = 65 mph =  \frac{65\times 1609}{3600} = 29.05 m/s

Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:

W = \frac{1}{2}m\Delta v^{2}

W = \frac{1}{2}m\times (v^{2} - u^{2})

W = \frac{1}{2}2500\times (29.05^{2} - 20.11^{2})

W = 549.36 kJ

3 0
3 years ago
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