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rusak2 [61]
3 years ago
12

You place a book on top of a spring and push down, compressing the spring by 10 cm. When you let go of the book, it is pushed up

by the spring. Which statement describes what happens to the energy of the spring-book-system?
Physics
2 answers:
enot [183]3 years ago
4 0
At First, there is chemical Energy( in your muscels) which is Used to Push down the spring. This Energy becomes the Energy of the spring, which increases until you stop pushing. If you Put your hand away, the Energy of the spring will become kinetic energ. This Energy is at the highest Level the Moment the book ist Leaving the spring. Afterwards, the kinetic Energy decreases while the Gravitational Potential Energy increases.
DochEvi [55]3 years ago
3 0

Answer: The gravitational potential energy of the system increases.

Explanation:

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An object on a planet has a mass of 243 kg. What is the acceleration of the
Vesna [10]

Answer:

The gravitational acceleration of a planet of mass M and radius R

a = G*M/R^2.

In this case we have:

G = 6.67 x 10^-11 N (m/kg)^2

R = 2.32 x 10^7 m

M = 6.35 x 10^30 kg

Now we can compute:

a = (6.67*6.35/2.32^2)x10^(-11 + 30 - 2*7) m/s^2 = 786,907.32 m/s^2

The acceleration does not depend on the mass of the object.

3 0
3 years ago
How does increasing the distance between charged objects affect the electric force between them? the electric force increases be
konstantin123 [22]

the electric force decreases because the distance has an indirect relationship to the force

Explanation:

The electric force between two objects is given by

F=k \frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the distance between the two objects

As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

3 0
3 years ago
Read 2 more answers
50 grams of ice cubes at -15°C are used to chill a water at 30°C with mass mH20 = 200 g. Assume that the water is kept in a foam
Arada [10]

Answer : The final temperature is, 25.0^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ice = 2.09J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ice = 50 g

m_2 = mass of water = 200 g

T_f = final temperature = ?

T_1 = initial temperature of ice = -15^oC

T_2 = initial temperature of water = 30^oC

Now put all the given values in the above formula, we get:

50g\times 2.09J/g^oC\times (T_f-(-15))^oC=-200g\times 4.184J/g^oC\times (T_f-30)^oC

T_f=25.0^oC

Therefore, the final temperature is, 25.0^oC

5 0
3 years ago
In the morning, if you walk through a grassy lawn or field, quite often your feet will get very wet. What is the liquid generall
Dima020 [189]
The liquid is called condensation and its generally formed when water vaor in the air cools down rapidly and collects around or on an object forming water droplets. 
6 0
3 years ago
A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of
mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m;    &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

                                  = (2.1 × 10⁷ + 6.37 × 10⁶) m

                                  = 27370000

                                  = 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷  × 0.532655 )

                              = 3818.215

                              = 3.818 × 10³

                             = 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × \frac{r}{V_o}

            = 2 × 3.14 × \frac{2.737*10^7}{3.818*10^3}

            = 45019.28

            = 4.5 × 10 ⁴ s

6 0
3 years ago
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