Answer:
151200 minutes.
Explanation:
From the question given above, the following data were obtained:
Time (in week) = 15 weeks
Time (in min) =?
Next, we shall convert 15 weeks to days. This can be obtained as follow:
1 week = 7 days
Therefore,
15 weeks = 15 weeks × 7 days / 1 week
15 weeks = 105 days
Next, we shall convert 105 days to hours. This can be obtained as follow:
1 day = 24 h
Therefore,
105 days = 105 days × 24 h / 1 day
105 days = 2520 h
Finally, we shall convert 2520 h to mins. This can be obtained as follow:
1 h = 60 mins
Therefore,
2520 h = 2520 h × 60 mins / 1 h
2520 h = 151200 mins
Thus, 15 weeks is equivalent to 151200 minutes.
Dalton's law of partial pressures states that the total pressure of a mixture of gases is the sum of the partial pressures of its components:
\text {P}_{\text{Total}} = \text P_{\text {gas 1}} + \text P_{\text {gas 2}} + \text P_{\text {gas 3}} ...P
Total
=P
gas 1
+P
gas 2
+P
gas 3
...
The answer would have to be d because heat rises
THE RADIUS OF THE TENTH ORBIT IN A HYDROGEN ATOM IS 52.9A°
<h3>How does an electron orbit work? </h3>
The three-dimensional area covering the nucleus of an atom is called electron orbital. Electrons sometimes fill low-energy orbitals which are closer to the nucleus before filling the higher ones. They mostly fill the orbitals as singly as they can and that filling is known as Hund’s rule. In the wave-like property, electrons don’t orbit a nucleus in the way a planet orbits the sun but however, but they exist as standing waves. The lowest energy possible an electron can take is the same as the fundamental frequency of a wave on a string.
the radius of the first orbit =0.0529nm
radius ∝ n²/z
radius of 10th orbit =(0.0529×100)nm=52.9A°
To learn more about Electron orbit,visit:
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The percentage of Calcium carbonate in chalk = 100%
<h3>Further explanation</h3>
Given
1.51 g piece of chalk produces 0.665 g of carbon dioxide
Required
percentage of calcium carbonate
Solution
Reaction
CaCO3 (s) + 2 HCl (aq) → CaCl2 (aq) + H2O (l) + CO2 (g)
mol CO2 :
= 0.665 g : 44 g/mol
= 0.015
From the equation, mol CaCO3 = mol CO2 = 0.015
mass CaCO3 :
= mol x MW
= 0.015 x 100
= 1.5 g
