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I am Lyosha [343]
2 years ago
7

Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter

of solution,what is the molarity of H+?
Answer in units of M doing mole/liter doesn't work
Chemistry
2 answers:
Nikitich [7]2 years ago
4 0
As, using formula.........0.054/(.667/18)
=.o54/.037
=1.45 approx

so the answer
Degger [83]2 years ago
3 0
The answer is 0.612M

Find the molarity of the diprotic acid.
667ml ÷ 1000ml = 0.667L
M = 0.054 ÷ 0.667 = <span>0.08095952023 = 0.081 M H2SO4
There are 2 H+ for every one H2SO4, so the molarity of H+ is twice the molarity of the acid.
2 x 0.081M = 0.162M
</span>
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Explanation:

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Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:R=0.0821\frac{L\cdot atm}{mol\cdot K}

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V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}

V=0.56L \text{ } O_2

So, 0.80g of O_2(g) would occupy 0.56L at STP.

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