This question is incomplete because the options are missing; here are the options:
Which of the following is LESS dense than water?
The spoon
The glass
The tablets
The bubbles
The correct answer to this question is The bubbles
Explanation:
In general, the density of materials and substances affects their buoyancy. This implies in water less dense materials will float and those with higher density will sink. In the situation presented, the only element that is less dense than water are bubbles; this is shown by the movement of the bubbles as these originate in the bottom of the glass of water but they rise to the surface, which shows they are less dense than water.
Answer:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is used mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Explanation:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
You would expect snow to fail at the peak or the top because the weather is coldest there.
Answer:
the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
Explanation:
Given the data in the question;
+ 
⇄ 
Formation constant Kf
Kf = / ( [][] ) = 5.0 × 10¹⁰
Now,
[] = 
; ∝₄ = 0.35
so the equilibrium is;
+ 
⇄ + 4H⁺
Given that; 
= { 1 mol reacts with 1 mol }
so at equilibrium, = = x
∴
+ ⇄
x + x 0.010-x
since Kf is high, them x will be small so, 0.010-x is approximately 0.010
so;
Kf = / ( [][] ) = / ( [][] ) = 5.0 × 10¹⁰
⇒ / ( [][] ) = 5.0 × 10¹⁰
⇒ 0.010 / ( [x][ 0.35 × x] ) = 5.0 × 10¹⁰
⇒ 0.010 / 0.35x² = 5.0 × 10¹⁰
⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 5.7142857 × 10⁻¹³
⇒ x = √(5.7142857 × 10⁻¹³)
⇒ x = 7.559 × 10⁻⁷
Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
