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I am Lyosha [343]

2 years ago

7

Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter

of solution,what is the molarity of H+?
Answer in units of M doing mole/liter doesn't work

2 answers:

Nikitich [7]2 years ago

4 0

As, using formula.........0.054/(.667/18)
=.o54/.037
=1.45 approx

so the answer

Degger [83]2 years ago

3 0

The answer is 0.612M

Find the molarity of the diprotic acid.
667ml ÷ 1000ml = 0.667L
M = 0.054 ÷ 0.667 = <span>0.08095952023 = 0.081 M H2SO4
There are 2 H+ for every one H2SO4, so the molarity of H+ is twice the molarity of the acid.
2 x 0.081M = 0.162M
</span>

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A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

3 years ago

1. As the temperature of the gas in a balloon decreases, which of the following occurs? The volume of the balloon increases. ***

timama [110]

Answer 1:
Correct Answer: T<span>he average kinetic energy of the gas decreases.
</span>Reason:
From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume, n = number of moles of gas, R = gas constant and T = temperature.

From above equation, it can be seen that, Temp. as a direct relation with Pressure and Volume. Hence, as temperature of the gas in a balloon decreases, pressure and volume also decreases.

Also, from kinetic theory of gases, we know that, kinetic energy of gas increases with increasing temp. Hence, average kinetic energy of the gas decreases with decreasing temp.

Answer 2:
Correct answer: Out
Reason:
From the ideal gas equation, we know that PV = nRT
where, P = pressure, V = volume, n = number of moles of gas, R = gas constant and T = temperature.

Therefore, when a sealed syringe is heated, it's temp. will increase. This, will result in expansion of gas i.e volume will increase. Hence, <span>syringe plunger move in outwards direction.

Answer 3: Volume = 6046 L
Reason:
</span>From the ideal gas equation, we know that PV = RT
where, P = pressure, V = volume, R = gas constant and T = temperature.<span>
Given: P1 = 99 kPa, V1 = 3000 L, T1 = 312 K, P2 = 45.5 KPa and T2 = 289 K.

Therefore, we have: </span> $\frac{\text{P1 V1}}{\text{P2 V2}} = \frac{\text{R T1}}{\text{R T2}}$
Thus, $\frac{\text{99 3000}}{\text{45.5 V2}} = \frac{\text{R 312}}{\text{R 289}}$

Hence, V2 = 6046 L

Answer 4:
Correct Answer: It increases
Reason:
We know that, pressure of gas, it directly proportional to temp. Hence, when the temp. of as is increases. Total pressure of gas mixture increases. This is because, partial pressure of individual component (in present case oxygen) increases.

Answer 5:
Correct answer: 18.5 kPa
Reason:
We know that, total pressure is the sum of the partial pressures of the gases present in it. Mathematically, it can be expressed as:

Ptot = PO2 + PHe + PCO2

Therefore, partial pressure of oxygen, <span>PO2:</span>

PO2 = Ptot − PHe − PCO2

= 101.4 − 82.5 − 0.4

=18.5 kPa.

Answer 6:

Correct Answer: Argon

Reason:

<span>Inert gases are the best choice for inflating a balloon that must remain inflated for a long period of time. Among given options, both neon and argon are inert gas, But, atomic weight of Ar is 40g/mol, while is more than that of neon (20 g/mol). Hence,. Argon gas is preferred over neon gas. </span>

4 0

3 years ago

Read 2 more answers

Which of the following is the test for oxygen has?

dem82 [27]

A or B depends on what you mean by lit or glowing but when you place a wooden split in the sample the gas must reignite but there can be some confusion between hydrogen and oxygen mainly because a splint can cause a slight popping sound while it reignites but hydrogen pops are more violent and can most time extinguish the splint.

5 0

3 years ago

Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a

dmitriy555 [2]

<u>Answer:</u> The fraction of atom's mass contributed by nucleus is 0.99

<u>Explanation:</u>

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is $_2^4\textrm{He}$

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = $6.64648\times 10^{-24}g$

Mass of 1 electron = $9.10939\times 10^{-28}g$

Calculating the mass contributed by the nucleus = $m_{He}-2(m_e)$

Mass of the nucleus of He-4 atom = $6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}$

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}$

Putting values in above equation, we get:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99$

Hence, the fraction of atom's mass contributed by nucleus is 0.99

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2 years ago

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Irina-Kira [14]

Answer:a

Explanation:

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