Sulfuric acid (H2SO4) is a very strong diprotic acid. If 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter of solution,what is the molarity of H+? Answer in units of M doing mole/liter doesn't work
2 answers:
As, using formula.........0.054/(.667/18) =.o54/.037 =1.45 approx so the answer
The answer is 0.612M Find the molarity of the diprotic acid. 667ml ÷ 1000ml = 0.667L M = 0.054 ÷ 0.667 = <span>0.08095952023 = 0.081 M H2SO4 There are 2 H+ for every one H2SO4, so the molarity of H+ is twice the molarity of the acid. 2 x 0.081M = 0.162M </span>
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