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iVinArrow [24]
3 years ago
13

Which type of matter has a definite composition througout and is made of more than on type of element

Chemistry
1 answer:
zvonat [6]3 years ago
4 0

Answer:

Compound

Explanation:

It has a definite composition throughout and can be made of more than one type of element.

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Problem 12.002 the molar analysis of a gas mixture at 30°c, 2 bar is 40% n2, 50% co2, 10% ch4. determine
andreev551 [17]
The problem is incomplete. However, there can only be two probable questions for this problem. First, you can be asked the individual partial pressures of each gas. Second, you can be asked the volume occupied by each gas. I can answer both cases for you.

1.

Let's assume ideal gas.
Pressure for N₂: 2 bar*0.4 = 0.8 bar
Pressure for CO₂: 2 bar*0.5 = 1 bar
Pressure for CH₄: 2 bar*0.1 = 0.2 bar

2. For the volume, let's find the total volume first.

V = nRT/P = (1 mol)(8.314 J/mol-K)(30 +273 K)/(2 bar*10⁵ Pa/1 bar)
V = 0.0126 m³
Hence,
Volume for N₂: 0.0126 bar*0.4 = 0.00504 m³
Volume for CO₂: 0.0126*0.5 = 0.0063 m³
Volume for CH₄: 0.0126*0.1 = 0.00126 m³
3 0
3 years ago
Mitosis and Meiosis Lab Report
poizon [28]

Answer:

Mitosis and Meiosis Lab Report

Instructions: In the Mitosis and Meiosis lab, you investigated sexual and asexual reproduction as well as the processes of cellular division by mitosis and meiosis. Record your observations in the lab report below. You will submit your completed report.

________________________________________

Name and Title:  

Mitosis and Meiosis Lab Report.  

Objective(s):  

To learn and explore what mitosis and meiosis is and what they do.  

Hypothesis:

Record your predictions during the zoo tour section of the lab in the data chart.

Procedure:

First, go into the mitosis and meiosis cycles. Then look at what happens when a sex cell from a female tiger is combined with a sex cell from a male tiger. Then investigate what happens when two starfish reproduce asexually. Then write down the predictions about how each organism will replicate. Then, keep track on whether or not the forecast was right.

Data:  

Record your data from the zoo tour in the data chart below. Be sure to fill in the chart completely.

Zoo Organism Reproduction Prediction

(sexual, asexual, or both) Reproduction Result

(sexual, asexual, or both)

Elephant Sexual Sexual

Whiptail lizard Asexual Asexual

Parrot Sexual Sexual

Redwood tree  Both Both

Amoeba Asexual Asexual

Jellyfish Asexual Both

Conclusion:  

Your conclusion will include a summary of your lab results and an interpretation of the results. Please write in complete sentences.

1. List one-way mitosis and meiosis are the same and one way they are different.

Meiosis has 2 cell divisions, but mitosis has just one cell division. Since the parent cell develops diploid cells, meiosis I is the same as mitosis. The distinction between meiosis and mitosis is that after the whole process, meiosis produces genetically distinct haploid daughter cells, while mitosis produces genetically identical diploid daughter cells.

2. What is one advantage and one disadvantage of sexual reproduction?

The greatest benefit of sexual reproduction is that it aids in the development of offspring that are well suited to environmental environments due to genetic differentiation. As a result, the nation has a diverse range of descendants. The downside is that it needs two parents and takes longer than asexual reproduction.

3. What is one advantage and one disadvantage of asexual reproduction?

Asexual reproduction has the advantage of requiring only one parent, taking a short amount of time, and producing genetically identical offspring. The only drawback is that when there is a catastrophe, the mortality rate is poor due to the generation of genetically identical offspring.

4. Some living organisms are capable of both asexual and sexual reproduction. Explain how this can be an advantage.

To produce offspring, the organism may use either sexual or asexual reproduction. If it is difficult to find a mate, the living being will use asexual reproduction to produce offspring quickly. Sexual reproduction is possible because the individual requires genetically distinct offspring for survival.

Explanation:

Try to paraphrase evrything. I already paraphrased the procedure but i reccomend using the website "quillbot" to paraphrase evrything else so you dont get in trouble! If you have any qustions im here to answer ;)

6 0
3 years ago
Read 2 more answers
What happens when we decrease the height of an inclined plane?
Mashutka [201]

Answer:

b is the answer.

Explanation:

5 0
3 years ago
Does sodium (Na) and argon (Ar) on the periodic table have similar properties? Explain in terms of location on the periodic tabl
iVinArrow [24]

Sodium (Na) and Argon (Ar) on the periodic table does not have similar properties.

PERIODIC TABLE:

  • Periodic table is the organized table that showcases the position of elements. The periodic table is organized into groups and periods.

  • Groups of the periodic table is in a vertical format labeled 1 - 7 while the period is in a horizontal format labeled 1 - 7.

  • Elements in the same group have the same number of valence electrons and hence, possess similar chemical properties.

  • Sodium (Na) belongs to group 1 while argon is a noble gas, hence, they are not in the same group of the periodic table and cannot have same properties.

Learn more at: brainly.com/question/24089206?referrer=searchResults

6 0
2 years ago
Extend the aufbau sequence through an element that has not yet been identified, but whose atoms would completely fill 7p orbital
Thepotemich [5.8K]

Answer:

<u>Number of electrons</u> = 118

<u>Electronic configuration</u>: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

Explanation:

Given: A chemical element that has completely filled 7p orbital.

According to this, the principal occupied electron shell or the <u>valence shell of such an element is 7p.</u>

⇒ the principal quantum number <u>(n) for the valence shell is 7.</u>

∴ this element belongs to the period 7 of the periodic table.

Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.

Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a <u>completely filled 5f, 6d, 7s and 7p orbitals</u>.

Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

And, the <u>number of electrons</u> = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = <u>118</u>.

<u>Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.</u>

7 0
3 years ago
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