Answer: 51.45 grams of excess reagent is left after the completion of reaction.
Explanation: For the calculation of moles, we use the formula:
....(1)
Given mass = 92 grams
Molar mass = 28g/mol
Putting values in equation 1, we get:

- For

Given mass = 112 grams
Molar mass = 116g/mol
Putting values in equation 1, we get:

The reaction follows:

By Stoichiometry,
2 moles of
reacts with 3 moles of silicon
So, 0.965 moles of
reacts with =
= 1.4475 moles of Silicon.
As, the moles of silicon is more than the required amount and is present in excess.
So, the excess reagent for the reaction is Silicon.
Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles
To calculate the amount of Silicon left in excess is calculated by using equation 1:

Amount of Silicon in excess will be 51.45 grams.
This form of the oxygen molecule is Ozone, O3.
1) Molar mass C8H9NO2
Element Atomic mass # of atoms mass
g/mol g
C 12 8 12*8 = 96
H 1 9 1*9 = 9
N 14 1 14*1 = 14
O 16 2 16*2 = 32
molar mass = 96 + 9 + 14 + 32 = 151 g/mol
2) Number of mols in a tablet
# of moles = mass / molar mass = 0.500 g / 151 g/mol = 0.003311 moles
3) 3 doses * 2 tablets * 0.003311 moles / tablet = 0.020 moles
Answer:
92.4 grams.
Explanation:
- From the balanced reaction:
<em>CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,</em>
1.0 mole of CaCO₃ reacts with 2.0 moles of HCl to produce 1.0 mole of CaCl₂, 1.0 mole of CO₂, and 1.0 mole of H₂O.
- We need to calculate the no. of moles of (104 g) of CaCO₃:
<em>no. of moles of CaCO₃ = mass/molar mass</em> = (104 g)/(100.08 g/mol) = <em>1.039 mol.</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CaCO₃ produce → 1.0 mole of CaCl₂.
∴ 1.039 mole of CaCO₃ produce → 1.039 mole of CaCl₂.
∴ The amount of CaCl₂ produced = no. of moles x molar mass = (1.039 mol)(110.98 g/mol) = 114.3 g.
∵ percent yield of the reaction = [(actual yield)/(theoretical yield)] x 100.
Percent yield of the reaction = 80.15%, theoretical yield = 115.3 g.
<em>∴ actual yield = [(percent yield of the reaction)(theoretical yield)]/100 </em>= [(80.15%)/(115.3 g)] / 100 = <em>92.42 g ≅ 92.4 g.</em>
Answer:
3.43 moles
Explanation:
To convert moles into grams you must take the number of grams and divide it by the atomic mass of the compound.
in this case, grams is 151 and N2O has an atomic mass of 44.013
so your equation would look like
151/44.013=3.430804535
your answer would be 3.43 moles