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Answer:
a) The mass flow rate of water is 14.683 kilograms per second.
b) The pressure difference across the pump is 245.175 kilopascals.
Explanation:
a) Let suppose that pump works at steady state. The mass flow rate of the water (), in kilograms per second, is determined by following formula:
(1)
Where:
- Pump power, in watts.
- Efficiency, no unit.
- Gravitational acceleration, in meters per square second.
- Hydrostatic column, in meters.
If we know that ,
,
and
, then the mass flow rate of water is:
The mass flow rate of water is 14.683 kilograms per second.
b) The pressure difference across the pump (), in pascals, is determined by this equation:
(2)
Where is the density of water, in kilograms per cubic meter.
If we know that ,
and
, then the pressure difference is:
The pressure difference across the pump is 245.175 kilopascals.
Given:
Wall's inside temperature,
Room air temperature,
Solution:
To calculate percentage max relative humidity, we make use of steam table for saturated pressure of wall and air:
From steam table:
At :
At :
Now,
(RH)_{max} = 68.58%
Therefore, max Relative Humidity of the air before the occurrence of condensation in wall is 68.85%