Two metallic terminals protrude from a device. The terminal on the left is the positive reference for a voltage called vx (the o
ther terminal is the negative reference). The terminal on the right is the positive reference for a voltage called vy (the other terminal being the negative reference). If it takes 1 mJ of energy to push a single electron into the left terminal, determine the voltages vx and vy.
2 answers:
Answer:
vx=6.242PV
vy=-6.242PV
Explanation:
Two metallic terminals protrude from a device. The terminal on the left is the positive reference for a voltage called vx (the other terminal is the negative reference). The terminal on the right is the positive reference for a voltage called vy (the other terminal being the negative reference). If it takes 1 mJ of energy to push a single electron into the left terminal, determine the voltages vx and vy.
Here 1mj of energy is needed to an electron into the other terminal
voltage of an electron
Recall that E=IVt(product of power and time
but Q=quantity of charge is it (measured in coulombs)
E/Q=V
Ve=
0.6242*10^16
6.242*10^15
6.242PV(P=Peta=10^15)
voltage ve=6.242PV
Ve is used as Vy
The voltage vf is
Vf=
Vf=-6.242*10^15
vf=-6.242PV
therefore, vf is designated as vy
the voltages are of the same magnitude but in different direction
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Answer:
The answers are as follow:
a) 10 mm
b) 12.730 N/
c) 127.307 N/
d) 0.25
Explanation:
d1 = 10mm , L1 = 40 mm, L2 = 50 mm, reduction in area = 90% = 0.9
Force = F =1000 N
let us find initial area first, A1 = pi* = 78.55
using reduction in area formula : 0.9 = (A1 - A2 ) / A1
solving it will give, A2 = 0.1 A1 = 7.855
a) The specimen elongation is final length - initial length
50 - 40 = 10 mm
b) Engineering stress uses the original area for all stress calculations,
Engineering stress = force / original area = F / A1 = 1000 / 78.55
Engineering stress = 12.730
c) True stress uses instantaneous area during stress calculations,
True fracture stress = force / final area = F / A2 = 1000 / 7.855
True Fracture stress = 127.30
e) strain = change in length / original length
strain = 10 / 40 = 0.25