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posledela
3 years ago
7

Please can someone help me with INTERIM CHECKPOINT Math problems

Mathematics
1 answer:
gogolik [260]3 years ago
8 0
The answer will be -32
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15%. 480-72=408
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3 years ago
Please help equation in picture(geometry)
vovangra [49]

Answer:

2)SSS

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5)SSS

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8)SAS

Step-by-step explanation:

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Solve for the value of x in:<br> x^2+ 6x + 25 = 0
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3 0
3 years ago
An English professor assigns letter grades on a test according to the following scheme. A: Top 9% of scores B: Scores below the
sergeinik [125]

Answer:

The minimum score required for an A grade is 83.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 72.3 and a standard deviation of 8.

This means that \mu = 72.3, \sigma = 8

Find the minimum score required for an A grade.

This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.

Z = \frac{X - \mu}{\sigma}

1.34 = \frac{X - 72.3}{8}

X - 72.3 = 1.34*8

X = 83

The minimum score required for an A grade is 83.

5 0
3 years ago
Can some one help me please?
matrenka [14]

Answer:

i think its 4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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