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astra-53 [7]
3 years ago
13

The molecule CCI4 contains one double bond and three single bonds. True or False

Chemistry
1 answer:
kifflom [539]3 years ago
3 0

False

Explanation: Carbon is the central atom which has valency of 4 and can form 4 bonds to complete its octet. Each chlorine has valency of 1 and can form only one bond to complete its octet. Thus carbon can bond with four chlorine atoms through sharing of electrons to form four single bonds. Thus it cannot contain a double bond.

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Given a molecular formula, how would you calculate the molecular weight of a compound
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what would you be most likely to measure by immsering and object in water and seeing how much the water level rises
Katena32 [7]
Mass, if you know what element you are working with.
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3 years ago
If the solubility of sugar at 25ºC is 211 g/100 g H2O, what mass of sugar can be dissolved in 300 g of H2O?
ladessa [460]

Answer:

633 grams of sugar can be dissolved in 300 g of H₂O

Explanation:

Solubility is the measure of the ability of a certain substance to dissolve in another and form a homogeneous system.  Solubility is then the maximum amount of a solute that a solvent can receive and is expressed by concentration units.

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

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a ⇒ b

c ⇒ x

Then:

x=\frac{c*b}{a}

You can apply the rule of three as follows: if by definition of solubility in 100 grams of H₂O there are 211 grams of sugar, in 300 g of H₂O how much sugar is there?

sugar=\frac{300 grams of H_{2}O *211 grams of sugar}{100 grams of H_{2}O}

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<u><em>633 grams of sugar can be dissolved in 300 g of H₂O</em></u>

7 0
2 years ago
Read 2 more answers
Joan needs a 0.053-M solution of HCl, but only has access to 2.12-M HCl, a 10-mL graduated pipet, and a 25-mL volumetric flask.
dmitriy555 [2]

Answer:

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.

Explanation:

Molarity of HCl Joan has access to = M_1=2.12 M

Volume of 2.12 M of HCl Joan use = V_1=?

Molarity of HCl Joan desired = M_2=0.053 M

Volume of 0.053 M of HCl Joan can prepare = V_2=25 mL

M_1V_1=M_2V_2

V_1=\frac{M_2V_2}{M_1}

=\frac{0.053 M\times 25 mL}{2.12 M}=0.625 mL

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.

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3 years ago
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