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frosja888 [35]
3 years ago
15

C3H8 + O2 = How do i balance this equation?

Chemistry
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

C3H8 +5O2=3CO2 +4H2O

Explanation:

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 The   formula that would represent an ionic  compound  that is composed of calcium and iodide ions  is   CaI2

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Ionic compound  CaI₂ is formed  when Calcium form cation ( <em>a positively charged ion</em>) by losing 2 electrons while two iodine atoms form  anion ( <em>a negatively charged ion</em>)  by  gaining one electron each.

When writing down   formula of ionic compound, the formula  of cation  is written  first followed by anion  formula. therefore  Ca is written  first  followed by I.

The numeric subscript 2 after I(iodine) indicate that 2 atoms of iodine are involved  in bonding.

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Atoms of hydrogen can become helium atoms during a chemical reaction.<br> True<br> False
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3 years ago
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Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
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Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

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3 years ago
Which moon phase does a solar eclipse occur in?
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