6.9 x 10^-4 would be .00069 written in scientific notation
Answer:
In a chemical reaction, there is a change in the composition of the substances; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition.
Explanation:
Answer:

Explanation:
We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.
Step 1. Convert formula units to moles

Step 2. Convert moles to grams

Explanation:
Mole ratio of Oxygen to Hydrogen gas = 1 : 2.
If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.
However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)
Answer:
divergent
Explanation:
Plates move apart at a divergent boundary