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3 years ago

How is a responding variable different from a manipulated variable?

Physics

2 answers:

shtirl [24]3 years ago

8 0

Answer:

Explanation:

Bess [88]3 years ago

4 0

i think it is b

Explanation:

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2. What mechanism would you use to safely capture emissions?

devlian [24]

Carbon capture is the safest way to capture emission.

<u>Explanation:</u>

Emission of green house gases is one of the most lurking threat above humans. So one of the best ways to reduce emission is to capture the gases like carbon di-oxide or carbon monoxide, nitrous oxide etc. So mostly, the carbon di-oxide gas which is produced as waste is captured using adsorption, absorption, chemical looping etc.

In this method, they are captured from high source points like cement factory etc and then stored in a secluded region. Thus, the adsorption of these gases and then storing them in secluded region is the best option for capturing emission.

5 0

3 years ago

How do you solve #3 and #5?

julia-pushkina [17]

Answer:

your answers are correct i have done this many times

8 0

3 years ago

A positive point charge q1 = +5.00 × 10−4C is held at a fixed position. A small object with mass 4.00×10−3kg and charge q2 = −3.

Lelechka [254]

Answer:

Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.

Explanation:

Energy conservation law: In isolated system the amount of total energy remains constant.

The types of energy are

Kinetic energy.
Potential energy.

Kinetic energy $=\frac{1}{2} mv^2$

Potential energy = $\frac{Kq_1q_2}{d}$

Here, q₁= +5.00×10⁻⁴C

q₂=-3.00×10⁻⁴C

d= distance = 4.00 m

V = velocity = 800 m/s

Total energy(E) =Kinetic energy+Potential energy

$=\frac{1}{2} mv^2$ + $\frac{Kq_1q_2}{d}$

$=\frac{1}{2} \times 4.00\times 10^{-3}\times(800)^2 +\frac{9\times10^9\times 5\times10^{-4}\times(-3\times10^{-4})}{4}$

=(1280-337.5)J

=942.5 J

Total energy of a system remains constant.

Therefore,

E $=\frac{1}{2} mv^2$ + $\frac{Kq_1q_2}{d}$

$\Rightarrow 942.5 = \frac{1}{2} \times 4 \times10^{-3} \times V^2 +\frac{9\times10^{9}\times5\times 10^{-4}\times(-3\times 10^{-4})}{0.2}$

$\Rightarrow 942.5 = 2\times10^{-3}v^2 -6750$

$\Rightarrow 2 \times10^{-3}\times v^2= 942.5+6750$

$\Rightarrow v^2 = \frac{7692.5}{2\times 10^{-3}}$

$\Rightarrow v= 1961.19$ m/s

Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.

5 0

3 years ago

N which order did the events forming our solar system occur?

brilliants [131]

Answer:

The solar nebula became hot and dense because of that it pulling in more gas. This flattened into a rotating disk. It spun faster and faster, forming the Sun.

Explanation:

hope this helps

4 0

3 years ago

Read 2 more answers

The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the 10-g bullet is traveling at 300 m/s

Nadusha1986 [10]

Answer:

$d=6.874mm$