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3 years ago

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You have discovered an element that is a poor conductor of electricity, has a low melting point, and is a gas at room temperatur

e. How would you classify this element?
A.metal

B.metalloid

C.actinoid

D.nonmetal

1 answer:

NeX [460]3 years ago

6 0

AHHH ITS B SORRY I ACTUALLY KNOE THIS

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2.What two factors must be held constant for density to be a constant ratio?

irina1246 [14]

Answer:

Temperature and Pressure

Explanation:

Temperature and pressure cause change in volume.

So any change in volume will alter the ratio of density as given by equation of density.

Density = mass/ volume

Change in volume will alter the ratio.

Kindly mark it branliest if the answer is little bit satisfying.

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2 years ago

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HEMP ME ITS DUE BY MIDNIGHT

balu736 [363]

Answer:

Explanation:

Option B is the correct answer

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2 years ago

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Assuming that gasoline is 100% isooctane, that isooctane burns to produce only CO2CO2 and H2OH2O, and that the density of isooct

Aleksandr [31]

Answer:

1.12×10¹¹ kg of CO₂ are produced with 4.6×10¹⁰ L of isooctane

Explanation:

Let's state the combustion reaction:

C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O

Let's calculate the mass of isooctane that reacts.

Density = Mass / Volume

Density . Volume = Mass

First of all, let's convert the volume in L to mL, so we can use density.

4.6×10¹⁰ L . 1000 mL / 1L = 4.6×10¹³ mL

0.792 g/mL . 4.6×10¹³ mL = 3.64 ×10¹³ g

This mass of isooctane reacts to produce CO₂ and water, so let's determine the moles of reaction

3.64 ×10¹³ g . 1mol / 114 g = 3.19×10¹¹ mol

Ratio is 1:8 so 1 mol of isooctane can produce 8 moles of dioxide

Therefore 3.19×10¹¹ mol would produce (3.19×10¹¹ mol . 8) = 2.55×10¹² moles of CO₂

Now, we can determine the mass of produced CO₂ by multipling:

moles . molar mass

2.55×10¹² mol . 44 g/mol = 1.12×10¹⁴ g of CO₂

If we convert to kg 1.12×10¹⁴ g / 1000 = 1.12×10¹¹ kg

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3 years ago

Why is the mass in amu of a carbon-12 atom reported as 12.011 in the periodic table of the elements?

Bas_tet [7]

The mass of an element listed in the Periodic Table is the weighted average of all its naturally occurring isotopes.

Naturally occurring carbon is about

99 % carbon-12 (12.000 u) + 1 % carbon-13 (13.003 u).

That extra carbon-13 makes the <em>average atomic mass</em> greater than 12.000 u.

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3 years ago

Which path will a carbon atom most likely travel from CO2 in the atmosphere to glucose in the cell of a secondary consumer

SVETLANKA909090 [29]

Answer:

See the answer below

Explanation:

<em>The carbon will have to travel in the form of CO2 from the atmosphere to a primary producer (green plant), from there to a primary consumer (herbivorous animal), and finally to a secondary consumer.</em>

The primary producer (a green plant) would fix the carbon in the CO2 to carbohydrate through a process known as photosynthesis. The equation of the process is as shown below:

$6 CO_2 + 6 H_2O --> C_6H_1_2O_6 + 6 O_2$

The carbon, now in the form of carbohydrate, would then be picked up by an animal (a primary consumer) that feeds on the green plant. The carbon would eventually get into a secondary consumer when the secondary consumer feeds on the primary consumer that fed on the green plant.

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3 years ago