Resistance = Voltage/Current
Wattage = Voltage * Current
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That means the current drawn by the lamp is equal to 100 watts divided by 210 volts.
Resistance =
Given :
A race car moves along a circular track of radius 100m at a velocity of 25m/s.
To Find :
(a) What is the time taken to complete one lap of the circular track.
(b) What is the time taken for 10 laps.
Solution :
Circumference of circular track,
a) Time taken to complete one lap is :
b) Time taken to complete 10 laps is :
Hence, this is the required solution.
Answer:
The correct answer is;
The magnitude of the force is 35.12 N
Explanation:
To solve the question, we note that the friction is zero and the force causes motion of a stationary mass
One of the equations of motion is required such as
v² = u² + 2× a× s
Where
v = Final velocity = 5.93 m/s
u = Initial velocity = 0 m/s , object at rest
a = acceleration
s = distance moved = 32 meters
But v = Distance/Time = 32 m /5.4 s = 5.93 m/s
Therefore
5.93² = 2×a×32
or a = 35.12/ 64 = 0.55 m/s²
Therefore Force F = Mass m × Acceleration a
Where mass m = 64 kg
Therefore F = 64 kg×0.55 m/s² = 35.12 N
<h3><u>Answer;</u></h3>
A: by counting up each individual atom and make sure the atom numbers are the same in the reactants and the products
<h3><u>Explanation;</u></h3>
- <em><u>According to the law of conservation of mass, the mass of reactants should always be the same as the mass of the products in a chemical equation. </u></em>Therefore, <em><u>the number of atoms of each element in a chemical equation should always be the same on both sides of the equation, </u></em>that is the side of reactants and side of products.
- Thus, <em><u>any chemical equation requires balancing to ensure that the number of atoms of each element is equal in both sides of the equation</u></em>. Balancing is a try and error process that ensures that the law of conservation of mass holds.
- In this case, the balanced equation would be; 2Na +2H₂O → 2NaOH +H₂
Answer:
17.97m/s
Explanation:
Density of air (ρ)air=1.23 kg/m3, and
Air speed (V) =20 m/sec, pressure gradient along the streamline, ∂p/∂x = 100N/m^3.
The equation of motion along the stream line directions:
considering the momentum balance along the streamline.
γsinθ-∂p/∂x=ρV(∂V/∂x)
Neglecting the effect of gravity , then γ=ρg=0
So, ∂p/∂x= -ρV(∂V/∂x)
∂V/∂x= - 100/(20X1.23)= -4.0650407/S
Also δV/δx=∂V/∂x
∂V/∂x=-4.0650407/S and δx=0.5 m
δV = (-4.0650407/S) *(0.5m)
δV = -2.0325203 m/S
So net air speed will be V+δV= -2.0325203+20 ≅17.96748 m/s
Approximately, V+δV=17.97m/s.
