First we need to find the time in the air
d = 1/2gt^2 + vt
Since there is no inital vertical velocity
4.1 = 1/2 (9.8) t^2
8.2/9.8 = t^2
0.8367 = t^2
t = 0.9147s
Now we multiply by speed
7m/s x 0.9147s = 6.4m
Answer:
Distance, d = 778.05 m
Explanation:
Given that,
Force acting on the car, F = 981 N
Mass of the car, m = 1550 kg
Initial speed of the car, v = 25 mi/h = 11.17 m/s
We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:
Let d is the distance covered by car. Using second equation of motion as :
So, the car will cover a distance of 778.05 meters.
The magnitude and direction of the force on the charge is -12 N opposite the electric field
To calculate the force on a charge in an electric field, we make use of the formula below.
<u>Formula</u>
F = E×Q .......................... Equation 1
Where:
- F = Force on the charge
- E = Electric Field
- Q = charge
From the question,
Given:
Substitute these values into equation 1
Note: The negative sign indicates that the force is in the direction negative of the electric field.
Hence, The magnitude and direction of the force on the charge is -12 N opposite the electric field
Learn more about Electric Field here: brainly.com/question/14015797
The energy that the student shoud use in order to climb the stairs is equal to its increase in gravitational potential energy:
where m is the mass of the student, g the gravitational acceleration and
the variation of height. Plugging numbers into the equation, we find
The power required for the student to climb the stairs is equal to the work done divided by the time taken: