0kg
If the gravitational pull is zero and I multiply by mass I get a zero
We need to considerate only the horizontal component of the motion of the toy car.
The formula for the distance in a decelerated motion is:
s = s₀ + v₀·t - 1/2·a·t²
where:
s₀ = initial position = 0
v₀ = initial velocity = 1.21 m/s
t = time elapsed = 0.342 s
a = deceleration = 0.131 m/s²
Plugging in numbers:
s = 0 + 1.21×0.342 - 0.5×0.141×(0.342)²
= 0.406 m
Hence, the toy car traveled a distance of about 41 cm.
Answer:
when a force is applied by one object to a second object, an equal and opposite force is applied back on the first object
Explanation:
Answer:
<em>Explanation below</em>
Explanation:
<u>Speed vs Velocity
</u>
These are two similar physical concepts. They only differ in the fact that the velocity is vectorial, i.e. having magnitude and direction, and the speed is scalar, just the magnitude regardless of the direction. They are strongly related to the concepts of displacement and distance, which are the vectorial and scalar versions of the space traveled by a moving object. The velocity can be computed as

Where
is the position vector and t is the time. The speed is

To compute
, we only need to know the initial and final positions and subtract them. To compute d, we need to add all the distances traveled by the object, regardless of their directions.
Maggie walks to a friend's house, located 1500 meters from her place. The initial position is 0 and the final position is 1500 m. The displacement is

and the velocity is

Now, we know Maggie had to make three different turns of direction to finally get there. This means her distance is more than 1500 m. Let's say she walked 500 m in all the turns, then the distance is

If she took the same time to reach her destiny, she would have to run faster, because her average speed is

The answer would be erin out of all of them thank me later :)