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AveGali [126]
3 years ago
9

in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of th

e ball?
Physics
1 answer:
Nata [24]3 years ago
8 0

Answer:

R = 73.25 m

Explanation:

We have,

Initial speed of the ball is 27 m/s

It is projected at an angle of 40 degrees

The maximum range of the ball is given by :

R=\dfrac{u^2\sin2\theta}{g}

Plugging all the values we get :

R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m

So, the maximum range of the ball is 73.25 m

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A 4350 kg truck, driving 7.39 m/s, runs into the back of a stationary car. After the collision, the truck moves 4.55 m/s and the
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Mass of car = 1098 kg

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The bob of a pendulum swings back and forth with a total mechanical energy of 300 J. What is the kinetic energy of the bob when
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at the lowest point in the trajector, the kinetic energy of the bob is 300 J.

Explanation:

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In absence of friction, the total mechanical energy E remains constant. So we have:

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Learn more about kinetic energy:

brainly.com/question/6536722

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