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Strike441 [17]
3 years ago
5

2. A truck is traveling east through mud that is slowing down its speed. With west defined as negative, which of the following i

s correct? A. Both its velocity and acceleration are negative. B. Both its velocity and acceleration are positive. C. Its velocity is positive but its acceleration is negative. D. Its velocity is negative but its acceleration is positive. E. Both its velocity and acceleration are 0, since both properties are vectors.
Physics
1 answer:
Lynna [10]3 years ago
3 0

Hi! The answer is C

As west is defined as negative, the trucks velocity is positive, since its travelling east. But its speed (absolute value of velocity) is decreasing, that means that the acceleration is negative.  

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A line of charge starts at x = +x0 and extends to positive infinity. The linear charge density is λ = λ0x0/x. Determine the elec
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Explanation:

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dE=\dfrac{k\ dq}{x^2}..........(1)

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\lambda=\dfrac{dq}{dx}

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Hence, this is the required solution.

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3 years ago
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¿Qué nombre recibe un electrón que abandona el espacio interno del átomo dirigiéndose al exterior del átomo?
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3 years ago
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 38 ft/s2. what is the dist
e-lub [12.9K]

Convert 38 ft/s^2 to mi/h^2. Then we se the conversion factor > 1 mile = 5280 feet and 1 hour = 3600 seconds.

So now we show it > 38  \frac{ft}{s^2}  x  \frac{1mi}{5280ft} x  \frac{(3600s)^2}{(1h)^2} = 93272.27  \frac{mi}{h^2}

Then we have to use the formula of constant acceleration to determine the distance traveled by the car before it ended up stopping.

Which the formula for constant acceleration would be > v_2^2=v_1^2 + 2as

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When it stops the final velocity is (v_2=0)

Since the given is deceleration it means the number we had gotten earlier would be a negative so a = -93272.27

Then we substitute the values in....

0^2 = 50^2 + 2(-93272.27)s

0 = 2500 - 186544.54s

Isolate S next.

185644.54s= 2500

s =  2500/(185644.54)

s=0.0134


So we can say the car stopped at 0.0134 miles before it came to a stop but to express the distance traveled in feet we need to use the conversion factor of 1 mile = 5280 feet in otherwards > 0.0134 mi *  \frac{5280ft}{1mi}  = 70.8 ft
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4 0
3 years ago
In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
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Answer: F = 1391 N

Explanation:

The information given to you are:

Mass M = 1300 kg

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Therefore, the wrecking ball strikes the building with a force of 1391 N

3 0
3 years ago
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