Answer:
0.25 cm³.
Explanation:
We shall apply Boyle's law to find the solution . According to it
PV = constant where P is pressure and V is volume of the gas.
P₁ V₁ = P₂V₂
1 x .5 = 2 x V₂
V₂ = 0.25 cm³.
Answer:
The GPE, stored is 640 Joules
Explanation:
The given parameters are;
The given mass of the astronaut, m = 80 kg
The height of the top of the lunar lander to which the astronaut climbs, h = 5 m
The gravity strength on the moon, g = 1.6 N/kg
The Gravitational Potential Energy, GPE, stored is given according to the following equation;
GPE stored = m·g·h
Therefore, by substituting the known values, we have;
GPE Stored = 80 kg × 1.6 N/kg × 5 m = 640 Joules
The GPE, stored = 640 Joules.
Answer:
Solution
Explanation:
Solution:-
- The direction of motion of bus and car can be denoted by velocity vectors ( v1 and v2 ) respectively.
- On a page draw the velocity vector v1 vertically up denoting the direction of motion of bus from origin
- Similarly,draw the velocity vector v1 horizontally left denoting the direction of motion of car from origin.
- The force exerted by the car-bus interaction is always in the direction of motion.
- The force exerted by the bus is parallel to velocity vector as F1 and force exerted by the car is parallel to velocity vector as F2.
- The vector addition of of the two forces ( F1 and F2 ) will tell us the direction and magnitude of resultant force due to car-bus interaction.
- The resultant force will cause the car to be pushed off the road in the direction shown in the diagram.
The answer is D. The Moon's gravitational pull
The higher in the atmosphere, the less oxygen, and the more cold temperatures.
The material/moisture on the plane would freeze and damage the engine.
