Answer:
A.................. I think the answer
We have that the name (not chemical symbol) of the main group element in period 5 and group 3A is
Metalloid boron (B)
From the Question we are told that
The element belongs to
Period 5 and group 3A
Generally
Group 3A of the periodic table includes the metalloid boron (B), aluminum (Al), indium (In), and thallium (Tl) gallium (Ga),
Period 5 is possessed by the metalloid boron (B) of the Group 3A
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♥ In fact, the similarity of the numbers 85,19,17,4&2 is <span>that they are all divisors of 6460.
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Moles (mol) = mass (g) / molar mass (g/mol)
Mass of cysteine = 150 mg = 150 x 10⁻³ g
Molar mass of cysteine = 121.16 g/mol
Moles of cysteine = 150 x 10⁻³ g / 121.16 g/mol
= 1.238 x 10⁻³ mol
Cysteine has chemical formula as C₃H₇NO₂<span>S.
Hence, 1 mole of </span>C₃H₇NO₂S produces 7 moles of H atoms.
Hence, moles of H atoms present in the sample = 1.238 x 10⁻³ mol x 7
= 8.666 x 10⁻³ mol
According to the Avogadro's constant 1 mole of substance has 6.022 × 10²³ particles.
Hence,
number of H atoms in the sample = 8.666 x 10⁻³ mol x 6.022 × 10²³ mol
= 5.219 x 10²¹
Answer:
Conduction
Explanation:
Conduction is between one solid and another solid