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Slav-nsk [51]
3 years ago
8

Which layer of the atmosphere is between the exosphere and the mesosphere

Chemistry
2 answers:
Olenka [21]3 years ago
8 0

The atmosphere of earth is made of five main layers.

1) Troposphere : This is the lowest part of the atmosphere. Most of the air that makes up the atmosphere is present in this layer.

2) Stratosphere : This layer is present above troposphere and extends up to 50 km. It contains ozone layer which prevents the harmful ultraviolet rays from the sun from entering the lower troposphere

3) Mesosphere : The layer above stratosphere is known as mesosphere.

4) Thermosphere : The region lies above mesosphere.

5) Exosphere : The is the outermost region of the atmosphere.

From the above discussion we can see that the layer that lies between exosphere and mesosphere is Thermosphere

tigry1 [53]3 years ago
5 0
The Thermosphere is located between the Exosphere and Mesosphere.
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kogti [31]

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

3 0
3 years ago
What is the energy in joules of one photon of<br> microwaveradiation with a wavelength 0.122m?
pentagon [3]

<u>Answer:</u> The energy of photon is 162.93\times 10^{-26}J

<u>Explanation:</u>

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of photon = 0.122 m

Putting values in above equation, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{0.122m}\\\\E=162.93\times 10^{-26}J

Hence, the energy of photon is 162.93\times 10^{-26}J

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Answer:

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Explanation: brainliest

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Neutrons are neutral particles, so they don't change the charge of an atom. They do however, change the atomic mass, so the answer would be a. mass. 
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