Question

In plentiful air 3.0 parts of carbon react with 8.0 parts of oxygen to form carbon dioxide how much carbon is required to react with 1100 g of oxygen to leave only carbon dioxide after reaction?

Answer 1

Answer : The mass of carbon required is, 309.4 grams.

Explanation : Given,

Mass of oxygen = 1100 g

Molar mass of oxygen = 16 g/mol

Molar mass of carbon = 12 g/mol

First we have to calculate the moles of oxygen.

$\text{Moles of oxygen}=\frac{\text{Mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1100g}{16g/mol}=68.75mol$

Now we have to calculate the moles of carbon.

Moles of carbon = $\frac{3.0}{8.0}\times \text{Moles of oxygen}$

Moles of carbon = $\frac{3.0}{8.0}\times 68.75mol=25.78mol$

Now we have to calculate the mass of carbon.

$\text{Mass of carbon}=\text{Moles of carbon}\times \text{Molar mass of carbon}$

$\text{Mass of carbon}=25.78mol\times 12g/mol=309.4g$

Thus, the mass of carbon required is, 309.4 grams.