Answer:
Second Ionization energy
Explanation:
Let us write the reaction equation properly:
Ca⁺ → Ca²⁺ + e⁻
In the reaction above, we see that calcium goes from a single charge to being doubly charged by losing an electron.
Different atoms binds their valence electrons with different amount of energy. We must supply enough energy to remove the most losely held electrons in an atom. This amount of energy required is called the ionization energy.
The first ionization energy removes the outermost electron and makes the atom to become an ion.
Based on Le Chatelier's principle, if the equilibrium of a system is disturbed by changing the temperature, pressure or concentration, then it will shift in a direction to undo the effect of the induced change.
The given equilibrium is:
A + B ↔ AB
Removal of the reactant A implies that the concentration of A has decreased, therefore the equilibrium will shift in a direction to produce more of A. Thus, it will shift to the left and the rate of the reverse or backward reaction will increase.
Answer:
0.96 mol CO
Explanation:
We simply just use the reaction to help us find this:
Multiply it out and we get 0.96 as our answer.
Answer:
A and D are true , while B and F statements are false.
Explanation:
A) True. Since the standard gibbs free energy is
ΔG = ΔG⁰ + RT*ln Q
where Q= [P1]ᵃ.../([R1]ᵇ...) , representing the ratio of the product of concentration of chemical reaction products P and the product of concentration of chemical reaction reactants R
when the system reaches equilibrium ΔG=0 and Q=Keq
0 = ΔG⁰ + RT*ln Q → ΔG⁰ = (-RT*ln Keq)
therefore the first equation also can be expressed as
ΔG = RT*ln (Q/Keq)
thus the standard gibbs free energy can be determined using Keq
B) False. ΔG⁰ represents the change of free energy under standard conditions . Nevertheless , it will give us a clue about the ΔG around the standard conditions .For example if ΔG⁰>>0 then is likely that ΔG>0 ( from the first equation) if the temperature or concentration changes are not very distant from the standard conditions
C) False. From the equation presented
ΔG⁰ = (-RT*ln Keq)
ΔG⁰>0 if Keq<1 and ΔG⁰<0 if Keq>1
for example, for a reversible reaction ΔG⁰ will be <0 for forward or reverse reaction and the ΔG⁰ will be >0 for the other one ( reverse or forward reaction)
D) True. Standard conditions refer to
T= 298 K
pH= 7
P= 1 atm
C= 1 M for all reactants
Water = 55.6 M
Sodium chloride
aluminum oxide
potassium ???
copper bromide
iron (II) oxide
