Where does the electrical energy produced through wave energy come from?

Chemistry

1 answer:

Stella [2.4K]3 years ago

6 0

Oh the volcanos in the ocen

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The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is

Diano4ka-milaya [45]

Answer:

The half life time of first order reaction is 1.3 sec

Explanation:

Given:

First order rate constant $K = 0.54$ $M^{-1} s^{-1}$

Initial concentration $= 0.54$ M

From the formula of first order half life time,

$K = \frac{0.693}{t_{\frac{1}{2} } }$

So half life time is given by,

${t_{\frac{1}{y2} } } = \frac{0.693}{0.54}$

${t_{\frac{1}{y2} } } = 1.3$ sec

Therefore, the half life time of first order reaction is 1.3 sec.

4 0

3 years ago

A student balances the following redox reaction using half-reactions.

ICE Princess25 [194]

Answer: 6.

Explanation:

1) Aluminum

$Al^0-3e^----\ \textgreater \ Al^{3+}$

So each atom of aluminum lost 3 electrons to pass from 0 oxidation state to 3+ oxidation state.

2) Manganesium

$Mn^{2+}+2e^{-}---\ \textgreater \ Mn$

So, each ion of Mn(2+) gained 2 electrons pass from 2+ oxidation state to 0.

3) Balance

Multiply aluminum half-reaction (oxidation) by 2 and multiply manganesium half-raction (reduction) by 3:

$2Al^{0}-6e^{-}---\ \textgreater \ 2Al^{3+}

3Mn^{2+}+6e^{-}---\ \textgreater \ 3Mn^{0}$

4) Net equation

Add the two half-equations:

$2Al^{0}+3Mn^{2+}----\ \textgreater \ 2Al^{3+}+3Mn^{0}$

As you see the left side has 2 Al, 3Mn, and 3*2 positive charges.

The right side has 2 Al, 3 Mn, and 2*3 positive charges.

So, the equation is balanced.

5) Count the number of electrons involved.

As you see 2 atoms of aluminum lost 6 electrons (3 each).

That is the answer to the question. 6 electrons will be lost.

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2 years ago

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How many grams of CO2 are in 6 mol of the compound (this is a science question)?

denpristay [2]

0.136 C02 would be your answer

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3 years ago

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what is the correct conversion factor by which to multiply to convert moles of nitrogen to moles of ammonium nitrate (NH4NO3)

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Answer: