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zimovet [89]
3 years ago
11

Which of the following questions can use science as a method of inquiry?

Chemistry
2 answers:
Anton [14]3 years ago
4 0
Well B and C can be automatically dismissed. It is obviously not those.

As for A, science is not a method of inquiry.

So it has to be D. 

If I was right leave a rating and a thanks!
Sloan [31]3 years ago
4 0

Answer: A. When is creating a new vaccine appropriate?

D. How did the hole in the ozone layer form?

Explanation:

Science can answer questions or inquiry by utilizing suitable experimental methodology or by direct observation on something which can prove a reason for the cause of a natural phenomena.

Among the options given A. When is creating a new vaccine appropriate? and D. How did the hole in the ozone layer form? are correct. As these involves both experimental and observatory study to be answered.

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In the cells of the human body,oxygen molecules are used directly in a process that
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6 0
3 years ago
A gas has density 2.41 g/liter at 25°C and 770 mm Hg. Calculate it's molecular mass (R = 0.0821 L atm.mol-1K-1 ​
Evgesh-ka [11]

Answer:

Explanation:

Given : Density - 2.41 g/liter  

Temperature - 25° C  

Pressure : 770 mm Hg  

R = 0.0821 L atm mol-¹K-¹

 

Find : Molecular mass of gas

Solution : Ideal gas equation with respect to density will be : PM = dRT. In the formula, P is pressure, M is molecular mass, d is density, R is gas constant and T is temperature.

Keeping the values in equation-  

Pressure : 770 mm Hg = 1 atm  

Temperature : 273 + 25 = 298 K

 

M = dRT/P  

M = (2.41*0.0821*298)/1  

M = 58.96 gram/mol

Thus, the molecular mass of gas is 58.96 gram/mol.

8 0
3 years ago
If 21.00 mL of a 0.68 M solution of C6H5NH2 required 6.60 mL of the strong acid to completely neutralize the solution, what was
Andru [333]

Answer:

pH = 2.46

Explanation:

Hello there!

In this case, since this neutralization reaction may be assumed to occur in a 1:1 mole ratio between the base and the strong acid, it is possible to write the following moles and volume-concentrations relationship for the equivalence point:

n_{acid}=n_{base}=n_{salt}

Whereas the moles of the salt are computed as shown below:

n_{salt}=0.021L*0.68mol/L=0.01428mol

So we can divide those moles by the total volume (0.021L+0.0066L=0.0276L) to obtain the concentration of the final salt:

[salt]=0.01428mol/0.0276L=0.517M

Now, we need to keep in mind that this is an acidic salt since the base is weak and the acid strong, so the determinant ionization is:

C_6H_5NH_3^++H_2O\rightleftharpoons  C_6H_5NH_2+H_3O^+

Whose equilibrium expression is:

Ka=\frac{[C_6H_5NH_2][H_3O^+]}{C_6H_5NH_3^+}

Now, since the Kb of C6H5NH2 is 4.3 x 10^-10, its Ka is 2.326x10^-5 (Kw/Kb), we can also write:

2.326x10^{-5}=\frac{x^2}{0.517M}

Whereas x is:

x=\sqrt{0.517*2.326x10^{-5}}\\\\x=3.47x10^-3

Which also equals the concentration of hydrogen ions; therefore, the pH at the equivalence point is:

pH=-log(3.47x10^{-3})\\\\pH=2.46

Regards!

6 0
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The answer to this question is A- evaporation
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The smallest unit of an element that can exist either alone or in combination with other such particles of the same or different
Mekhanik [1.2K]

Answer

im not quite sure but I think the answer is <em>D atom</em><em> </em>

Explaination

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