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3 years ago

13

Do sound waves travel best in dense or less dense areas?

2 answers:

velikii [3]3 years ago

3 0

Thus, sound will travel at a slower rate in the denser object. If sound waves of the same energy were passed through a block of wood and a block of steel, which is more dense than the wood, the molecules of the steel would vibrate at a slower rate. Thus, sound passes more quickly through the wood, which is less dense.

valentinak56 [21]3 years ago

3 0

Answer:

less dense

Explanation:

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A diffusion coefficient KG was determined for the diffusion of a gas A through a stagnant film B [KG = 0.88 mol//h-ft2-atm].

Angelina_Jolie [31]

Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As, $N_{A} \propto (P_{A1} - P_{A2})$

$N_{A} = K_{G} \times (P_{A1} - P_{A2})$

Therefore, putting the given values into the above formula as follows.

$N_{A} = K_{G} \times (P_{A1} - P_{A2})$

= $0.88 \times (0.2 atm - 0.05 atm)$

= 0.132 $mol/h.ft^{2}$

Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 $mol/h.ft^{2}$

4 0

4 years ago

a sample of hydrogen gas (h2) is mixed with water vapor (h2o (g)). the make sure has a total pressure of 811 torr, and the water

Alborosie

Answer:

$n=0.430molH_2$

Explanation:

Hello!

In this case, considering the partial Dalton's law of partial pressures, we can notice that the total pressure equals the pressure of steam and the pressure of hydrogen, which can be determined as shown below:

$p_T=p_H+p_w\\\\p_H=811torr-12torr=799torr*\frac{1atm}{760torr}\\\\p_H=1.05atm$

Thus, by using the ideal gas law, we can compute the moles of hydrogen as shown below:

$PV=nRT\\\\n= \frac{PV}{RT}=\frac{1.05atm*10.0L}{0.082\frac{atm*L}{mol*K}*298K}\\\\n=0.430molH_2$

Best regards!

6 0

3 years ago

For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

<u>The reaction </u>

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

Moles of nitrogen monoxide

Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

2) <u>Limiting reagent</u>: $NO$

3) <u>Ammount of excess reagent</u>:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

8 0

3 years ago

1. A physician ordered 2.0 milligrams tetracycline to be given to a patient. If the tetracycline was available as 0.75 mg/mL of

Cerrena [4.2K]

Answer:

2.67 mL

Explanation:

The following data were obtained from the question:

Mass of tetracycline = 2 mg

Density of tetracycline = 0.75 mg/mL

Volume of tetracycline =?

We can obtain the volume of the tetracycline that should be given to the patient by applying the following equation:

Density = mass /volume

0.75 = 2 / volume

Cross multiply

0.75 × Volume = 2

Divide both side by 0.75

Volume = 2/0.75

Volume = 2.67 mL

Therefore, the volume of the tetracycline that should be given to the patient is 2.67 mL

6 0

3 years ago

Most of the energy released by nuclear fission is in the form of_________rays.

Margaret [11]

The answer to “most of the energy released by nuclear fission in the form of _____ rays.” is GAMMA RAYS

3 0

3 years ago