when copper sulfide is partially roasted in air (reaction with o2), copper sulfite is formed first. subsequently, upon heating,
1 answer:
The question is incomplete, complete question is:
When copper(I) sulfide is partially roasted in air (reaction with oxygen), copper(I) sulfite is formed first. subsequently, upon heating, the copper sulfite thermally decomposes to copper(I) oxide and sulfur dioxide. Write balanced chemical equations for these two reactions.
Answer:
The balanced chemical equations for these two reactions:
Explanation:
On partial roasting of copper sulfide in an air. The balanced chemical reaction is given as:
On further heating of copper(I) sulfite it get decomposes into copper oxide and sulfur dioxide. The balanced chemical reaction is given as:
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Answer:
3)The reaction is not at equilibrium and willproceed to the right.
Explanation:
The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.
It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
Q < Kc , reaction will proceed in forward direction.
Q > Kc , reaction will proceed in backward direction.
Q = Kc , reaction at equilibrium.
Given that:
Q =
K =
Since, Q < K , reaction is not at equilibrium and will proceed to right, in forward direction.