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Bas_tet [7]
3 years ago
14

Plllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllls help me

Chemistry
1 answer:
larisa [96]3 years ago
6 0

Answer:

Explanation:

equilibrium constant

Kc = [ C ]² / [ A ] [ B ]

= .5² / .2  x 3

= .4167

Let moles of A to be added be n

concentration of A unreacted becomes .2 + n M

increase of product C by .2 M will require use of A  and B be .1 M

So unreacted A = .2 + n - .1 = n + .1

Kc = [ C ]² / [ A ] [ B ]

.4167 = .7² / ( n + .1 ) ( 3 - .1 )

n + .1 = .4

n = . 3 moles .

So .3 moles of A to be added .

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3 years ago
An isotope of an element has the following symbol: 131 I How many electrons does it
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2 years ago
When an electron in a quantum system drops from a higher energy level to a lower one, the system __
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When an electron in a quantum system drops from a higher energy level to a lower one, the system<u> emit a photon.</u>

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4 0
2 years ago
What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?
Ilia_Sergeevich [38]

Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of O_{2} gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

6 0
3 years ago
With the aid of a balanced chemical equation explain Chemical Reactions and the Types Of Chemical Reaction
e-lub [12.9K]

Answer:

Answers

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4.)Mg(OH) 2 + 2HNO 3 → Mg(NO 3) 2 + 2H 2O.

5.)2NaClO 3 → 2NaCl + 3O 2

6.)4Al + 3O 2 → 2Al 2O 3

7.)N 2(g) + 3H 2(g) → 2NH 3(g)

Explanation:

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6 0
3 years ago
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