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3 years ago

Which two characteristics are important for soil or land that is used for farming ?

Physics

2 answers:

Tanzania [10]3 years ago

8 0

Answer:

deep, fertile soils. not too dry and not too wet. warm climate. land suitable for machinery.

I hope it's helpful!

GuDViN [60]3 years ago

8 0

Important agronomic soil properties include the soil water-holding capacity, infiltration rate, aggregation, temperature, organic matter content, and nutrient availability. This publication focuses on physical characteristics of soil that influence how soil retains water and water availability for crop production. Porous loamy soils are the richest of all, laced with organic matter which retains water and provides the nutrients needed by crops. Land that has a balance of sand, clay, dirt and rock that provides a stable, well-drained environment for plants is the best for farming.

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EastWind [94]

Answer:

the answer is c

Explanation:

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3 years ago

The power of the situation represents

lions [1.4K]

I think the answer is c but I'm not sure

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3 years ago

For a spring oscillating in simple harmonic motion, at what point will the velocity of

Crazy boy [7]

Answer:

equilibrium position.

Explanation:

In simple harmonic motion , velocity v(t) is given by,

v(t) = -ω A sin(ωt + φ)

where

ω = angular velocity of the corresponding circular motion

A = amplitude

t = time

φ = the initial angle of the corresponding circular motion when the motion begin.

v (t) get maximized when sin value is maximized , i.e. sin $\alpha$ =1

The particle has maximum speed when it passes through the equilibrium position.

6 0

4 years ago

A 0.09 g honeybee acquires a charge of +23 pc while flying. The earth's electric field near the surface is typically (100 N/C, d

hodyreva [135]

Answer:

$2.6\times 10^{-5}$

Explanation:

<u>Given:</u>

$m$ = mass of the honeybee = 0.09 g = $9\times 10^{-5}\ kg$

$q$ = charge on the honeybee = 23 pC = $2.3\times 10^{-11}\ C$

$E$ = electric field near the surface of earth = 100 N/C

<u>Assume:</u>

$g$ = acceleration due to gravity = $9.8\ m/s^2$

$W$ = weight of the honeybee

$F$ = electric force on the honeybee

$R$ = ratio of the electric force and the weight of the honeybee

We know that

$F = qE\,\,\, and\,\,\, W = mg\\\therefore R = \dfrac{F}{W}\\\Rightarrow R = \dfrac{qE}{mg}\\\Rightarrow R = \dfrac{2.3\times 10^{-11}\ C\times 100 N/C}{9\times 10^{-5}\ kg\times 9.8\ m/s^2}\\\Rightarrow R = 2.6\times 10^{-6}$

So, the ration of the electric force on the bee to its weight is $2.6\times 10^{-6}$ .

On multiplying this ration by 10, the ratio becomes $2.6\times 10^{-5}$ .

8 0

4 years ago

A planar loop consisting of seven turns of wire, each of which encloses 200 cm2, is oriented perpendicularly to a magnetic field

PtichkaEL [24]

Answer:

The induced current is 0.084 A

Explanation:

the area given by the exercise is

A = 200 cm^2 = 200x10^-4 m^2

R = 5 Ω

N = 7 turns

The formula of the emf induced according to Faraday's law is equal to:

ε = (-N * dφ)/dt = (N*(b2-b1)*A)/dt

Replacing values:

ε = (7*(38 - 14) * (200x10^-4))/8x10^-3 = 0.42 V

the induced current is equal to:

I = ε /R = 0.42/5 = 0.084 A

3 0

3 years ago

Read 2 more answers