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ziro4ka [17]
3 years ago
15

Which of the following correctly explains why it would be beneficial for an engineer to become a member of the Leadership in Ene

rgy and Environmental Design (LEED) program? a. In most states, nothing can be built without acceptance into this program. b. It can add to an engineer’s credentials and qualifications. c. It is necessary in order to meet federal regulations. I d. t is considered prestigious by other engineers.
Engineering
2 answers:
MariettaO [177]3 years ago
5 0

Answer:

B. It can add to an Engineer's credentials and qualifications.

Explanation:

Ksivusya [100]3 years ago
3 0

Answer:

B.  It can add to an engineer’s credentials and qualifications.

Explanation:

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After testing a model of a fuel-efficient vehicle, scientists build a full-sized vehicle with improved fuel efficiency. Which st
Mazyrski [523]
B evaluate the solution. Sorry if I'm wrong.
4 0
3 years ago
Technician A says high resistance causes an increase in current flow. Technician B says a higher than
Kryger [21]

The correct statement is: a higher than a normal voltage drop could indicate high resistance. Technician B is correct.

<h3>Ohm's law</h3>

Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical conditions are constant. Mathematically, it is expressed as

V = IR

Where

V is the potential difference

I is the current

R is the resistance

<h3>Technician A</h3>

High resistance causes an increase in current flow

V = IR

Divide both side by I

R = V / I

Thus, technician A is wrong as high resistance suggest low current flow

<h3>Technician B</h3>

Higher than normal voltage drop could indicate high resistance

V = IR

Thus, technician B is correct as high voltage indicates high resistance

<h3>Conclusion </h3>

From the above illustration, we can see that technician B is correct

Learn more about Ohm's law:

brainly.com/question/796939

8 0
2 years ago
The mechanical properties of a metal may be improved by incorporating fine particles of its oxide. Given that the moduli of elas
mojhsa [17]

Answer:

A) Upper bound modulus of elasticity; E = 165.6 GPa

B) Lower bound modulus of elasticity; E = 83.09 GPa

Explanation:

A) Formula for upper bound modulus is given as;

E = E_m(1 - V_f) + E_f•V_f

We are given;

E_m = 60 GPa

E_f = 380 GPa

V_f = 33% = 0.33

Thus,

E = 60(1 - 0.33) + 380(0.33)

E = (60 x 0.67) + 125.4

E = 165.6 GPa

B) Formula for lower bound modulus is given as;

E = 1/[(V_f/E_f) + ((1 – V_f)/E_m)]

E = 1/[(0.33/380) + ((1 – 0.33)/60)]

E = 1/(0.0008684 + 0.01116667)

E = 1/0.01203507

E = 83.09 GPa

3 0
2 years ago
Quantitative meaning
pychu [463]

Answer:

Explanation:

relating to, measuring, or measured by the quantity of something rather than its quality.Often contrasted with qualitative.

6 0
3 years ago
Read 2 more answers
An 80-percent-efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at a speed of 10 ft/s thr
Sladkaya [172]

Answer:

Part A

The mass plow rate, is approximately 97.0 lbm/s

Part B

The power used to overcome friction, is approximately 1.9 hp

Explanation:

The efficiency of the pump, η = 80%

The power input to the pump, P = 20 hp

The speed of the water through the pipe, v = 10 ft./s

The diameter of the pipe, d = 5.2 inches = 13/30 ft.

The free surface of the pool above the lake, h = 80 ft.

The density of the water, ρ = 62.4 lbm/ft.³

Part A

The mass plow rate, \dot m = Q × ρ

Where;

ρ = 62.4 lbm/ft³

Q = A × v

A = The cross-sectional area of the pipe

∴ Q = π·d²/4 × v = π × ((13/30 ft.)²)/4 × 10 ft.s ≈ 1.4748 ft.³/s

∴ The mass plow rate, \dot m ≈ 1.4748 ft.³/s × 62.4 lbm/ft.³ = 97.02752 lbm/s

The mass plow rate, \dot m ≈ 97.0 lbm/s

Part B

The power to pump the water at the given rate, P_w =  \dot m·g·h

∴ P_w =  97.02752 lbm/s × 32.1740 ft./s² × 80 ft. ≈ 14.1130725 Hp

P_w ≈ 14.1130725 Hp

The power output of the pump, P_{out} = 0.8 × 20 hp = 16 hp

Therefore, the power used to overcome friction, P_f = P_{out} - P_w

∴ P_f ≈ 16 hp - 14.1130725 Hp ≈ 1.8869275 hp

The power used to overcome friction,  P_f ≈ 1.9 hp

7 0
2 years ago
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