Answer:
0.12 dm³ or 120 cm³
Explanation:
Hi there!
so first step find the number of moles
number of moles = mass ÷ Ar ( since o is an element and when it is alone, it is a diatomic molecule {O2} )
number of moles = mass ÷ Ar
number of moles = 0.16 ÷ ( 16 × 2 )
= 0.16 ÷ 32
= 5 × 10 ( power -3)
1 mol of O2 = 24 dm³ or 24 000 cm³
5 × 10 ( power -3) of O2 = (5 × 10 ( power -3)) × 24
= 0.12 dm³
or
= (5 × 10 ( power -3)) × 24 000
= 120 cm³
The balanced chemical reaction is:
C6H6 + 9/2O2 = 6CO + 3H2O
We are given the amount of benzene to be used for the reaction. This will be the starting point for the calculations.
23.1 g C6H6 ( 1 mol C6H6 / 78.12 g C6H6 ) ( 6 mol CO / 1 mol C6H6 ) = 1.77 mol CO is produced from the reaction
The freezing point depression is calculated through the equation,
ΔT = (kf) x m
where ΔT is the difference in temperature, kf is the freezing point depression constant (1.86°C/m), and m is the molality. Substituting the known values,
5.88 = (1.86)(m)
m is equal to 3.16m
Recall that molality is calculated through the equation,
molality = number of mols / kg of solvent
number of mols = (3.16)(1.25) = 3.95 moles
Then, we multiply the calculated amount in moles with the molar mass of ethylene glycol and the answer would be 244.9 g.
Gases are less dense and the molecules are farther apart which means that it can be compressed