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Ket [755]
3 years ago
13

If the density of

Chemistry
1 answer:
Soloha48 [4]3 years ago
8 0
It’s the doubles I think not sure let me know if it’s true
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What is the correcr sum of Cl2+KBr=Br2+KCl
oksano4ka [1.4K]
Cl2 + 2KBr = Br2 + 2KCl
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In the following compound (HCl) How many electrons are gained and lost by each atom?
Verizon [17]

Explanation:

In HCL, one positive atom is given to chlorine from hydrogen so that it can complete it's octate. chlorine take one electron from hydrogen.

In NaCl, Sodium takes one electron from chlorine to complete its orbit with eight electrons. Chlorine gives one electron to sodium.

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The penguin has a ___ body that helps it to move quickly in water.
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The penguin has a sleek body that helps it to move quickly in water.
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2 years ago
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Which is a true statement?
labwork [276]

Answer: B) Particles can be filtered from a suspension.

Explanation: Colloids are solutions with particle size intermediate between true solutions and suspensions. They exhibit tyndall effect that is scattering of light.

Suspensions have large sized particles which settle when left undisturbed for sometime and thus can be filtered off easily.

The particle size in colloids is less and hence they do not settle under the effect of gravity.

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7 0
3 years ago
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The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calc
jek_recluse [69]

Answer: K_{sp}=1.25\times 10^{-14}

pK_{sp}=13.90

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}  

The equation for the ionization of magnesium phosphate is given as:

Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}

 When the solubility of Mg_3(PO_4)_2 is S moles/liter, then the solubility of Mg^{2+} will be 3S moles\liter and solubility of PO_4^{3-} will be 2S moles/liter.

Thus S = 0.173 g/L or \frac{0.173g/L}{262.8g/mol}=0.00065mol/L

K_{sp}=(3S)^3\times (2S)^2

K_{sp}=108S^5

K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}

pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90

5 0
2 years ago
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