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Mrrafil [7]
3 years ago
9

A bowling ball of 35.2kg, generates 218 kg.M/s units of momentum. What is the velocity of the bowling ball?

Chemistry
1 answer:
erik [133]3 years ago
7 0

Answer is: velocity of the bowling ball is 6.19 m/s.

Momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction in three-dimensional space.

m(ball) = 35.2 kg; mass of a bowling ball.

p(ball) = 218 kg·m/s; momentum of a ball.

v(ball) = p(ball) ÷ m(ball).

v(ball) = 218 kg·m/s ÷ 35.2 kg.

v(ball) = 6.19 m/s; velocity of a bowling ball.

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H^+ = acid
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Acids have a pH of below 7. The lower the number, the strongest the acid.
4 0
3 years ago
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When 47.2 J of heat is added to 13.4 g of a liquid, its
leva [86]

Answer: 2.02 J/g°C

Explanation:

To find the heat capacity, we have to manipulate the equation for heat.

q=mCΔT becomes C=q/(mΔT) to find heat capacity. Since we are given our values, we can plug in to find C.

C=\frac{47.2J}{13.4g*1.74°C}

*Please ignore the capital A in front of the °C. In order to have ° in the equaiton, the A pops up.

C=2.02J/g°C

8 0
3 years ago
How many grams of fluorine are contained in 8 molecules of boron trifluoride?
Lelu [443]
<h3>Answer:</h3>

             7.57 × 10⁻²² g of F

<h3>Solution:</h3>

Data Given:

                 Number of Molecules  =  8

                 M.Mass of BF₃ =  67.82 g.mol⁻¹

                 Mass of Fluorine atoms  =  ?

Step 1: Calculate Moles of BF₃

           Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Putting value,

            Moles  =   8 Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

            Moles  =  1.33 × 10⁻²³ mol

Step 2: Calculate Mass of BF₃:

                   Moles  =  Mass ÷ M.Mass

Solving for Mass,

                   Mass  =  Moles × M.Mass

Putting values,

                   Mass  =  1.33 × 10⁻²³ mol × 67.82 g.mol⁻¹

                   Mass  =  9.0 × 10⁻²² g

Step 3: Calculate Mass of Fluorine Atoms:

As,

                         67.82 g BF₃ contains  =  57 g of F

So,

                    9.0 × 10⁻²² g will contain  =  X g of F

Solving for X,

                       X =  (9.0 × 10⁻²² g × 57 g) ÷ 67.82 g

                        X  =  7.57 × 10⁻²² g of F

4 0
3 years ago
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