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Mrrafil [7]
3 years ago
9

A bowling ball of 35.2kg, generates 218 kg.M/s units of momentum. What is the velocity of the bowling ball?

Chemistry
1 answer:
erik [133]3 years ago
7 0

Answer is: velocity of the bowling ball is 6.19 m/s.

Momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction in three-dimensional space.

m(ball) = 35.2 kg; mass of a bowling ball.

p(ball) = 218 kg·m/s; momentum of a ball.

v(ball) = p(ball) ÷ m(ball).

v(ball) = 218 kg·m/s ÷ 35.2 kg.

v(ball) = 6.19 m/s; velocity of a bowling ball.

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If 3.289 x 10^23 atoms of potassium react with excess water, how many grams of hydrogen gas would be produced?
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Answer:

The amount in grams of hydrogen gas produced is 0.551 grams

Explanation:

The parameters given are;

Number of atoms of potassium, aₙ = 3.289 × 10²³ atoms

Chemical equation for the reaction is given as follows;

2K + 2H₂O \rightarrow KOH + H₂

Avogadro's number, N_A, regarding the number of molecules or atom per mole is given s follows;

N_A = 6.02 × 10²³ atoms/mole

Therefore;

The number of moles of potassium present = 3.289 × 10²³/(6.02 × 10²³) = 0.546 moles

2 moles of potassium produces one mole of hydrogen gas, therefore;

1 moles of potassium produces 1/2 mole of hydrogen gas, and 0.546 moles of potassium will produce 0.546/2 moles of hydrogen which is 0.273 moles of hydrogen gas

The molar mass of hydrogen gas = 2.016 grams

Therefore, 0.273 moles will have a mass of 0.273×2.016 = 0.551 grams.

The amount in grams of hydrogen gas produced = 0.551 grams.

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