Answer:
Explanation:
Far point = 17 cm . That means he can not see beyond this distance .
He wants to see at an object at 65 cm away . That means object placed at 65 has image at 17 cm by concave lens . Using lens formula
1 / v - 1 / u = 1 / f
1 / - 17 - 1 / - 65 = 1 / f
= 1 / 65 - 1 / 17
= - .0434 = 1 / f
power = - 100 / f
= - 100 x .0434
= - 4.34 D .
Answer:
a) 600 meters
b) between 0 and 10 seconds, and between 30 and 40 seconds.
c) the average of the magnitude of the velocity function is 15 m/s
Explanation:
a) In order to find the magnitude of the car's displacement in 40 seconds,we need to find the area under the curve (integral of the depicted velocity function) between 0 and 40 seconds. Since the area is that of a trapezoid, we can calculate it directly from geometry:
![Area \,\,Trapezoid=(\left[B+b]\,(H/2)\\displacement= \left[(40-0)+(30-10)\right] \,(20/2)=600\,\,m](https://tex.z-dn.net/?f=Area%20%5C%2C%5C%2CTrapezoid%3D%28%5Cleft%5BB%2Bb%5D%5C%2C%28H%2F2%29%5C%5Cdisplacement%3D%20%5Cleft%5B%2840-0%29%2B%2830-10%29%5Cright%5D%20%5C%2C%2820%2F2%29%3D600%5C%2C%5C%2Cm)
b) The car is accelerating when the velocity is changing, so we see that the velocity is changing (increasing) between 0 and 10 seconds, and we also see the velocity decreasing between 30 and 40 seconds.
Notice that between 10 and 30 seconds the velocity is constant (doesn't change) of magnitude 20 m/s, so in this section of the trip there is NO acceleration.
c) To calculate the average of a function that is changing over time, we do it through calculus, using the formula for average of a function:
![Average\,of\,f(x)=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx](https://tex.z-dn.net/?f=Average%5C%2Cof%5C%2Cf%28x%29%3D%5Cfrac%7B1%7D%7Bb-a%7D%20%5Cint%5Climits%5Eb_a%20%7Bf%28x%29%7D%20%5C%2C%20dx)
Notice that the limits of integration for our case are 0 and 40 seconds, and that we have already calculated the area under the velocity function (the integral) in step a), so the average velocity becomes:
![Avearage=\frac{600\,\,m}{40\,\,s}= 15\,\,\frac{m}s}](https://tex.z-dn.net/?f=Avearage%3D%5Cfrac%7B600%5C%2C%5C%2Cm%7D%7B40%5C%2C%5C%2Cs%7D%3D%2015%5C%2C%5C%2C%5Cfrac%7Bm%7Ds%7D)
Answer:
b
Explanation:
the location where an earthquake begin is called
Answer:
1.
Firstly removing off one strip and it leaves electrons behind, so the strip becomes positively charged.
2. The roll however is not negatively charged because it is "earthed " by the hand holding it, thus excess negatives repel each other away through the hand.
3.Tearing off the next strip and once more it leaves electrons behind, the new strip is also positively charged and will repel the first strip.
4. Then, tear two strips apart and one will leave electrons behind on the other. Meaning that one strip is positive and the other is negative and they will attract each other.
Answer:
![6.63\times 10^8\ N/C](https://tex.z-dn.net/?f=6.63%5Ctimes%2010%5E8%5C%20N%2FC)
Explanation:
Given that,
The magnitude of magnetic field, B = 2.21
We need to find the magnitude of the electric field. Let it is E. So,
![\dfrac{E}{B}=c\\\\E=Bc](https://tex.z-dn.net/?f=%5Cdfrac%7BE%7D%7BB%7D%3Dc%5C%5C%5C%5CE%3DBc)
Put all the values,
![E=2.21\times 3\times 10^8\\\\=6.63\times 10^8\ N/C](https://tex.z-dn.net/?f=E%3D2.21%5Ctimes%203%5Ctimes%2010%5E8%5C%5C%5C%5C%3D6.63%5Ctimes%2010%5E8%5C%20N%2FC)
So, the magnitude of the electric field is equal to
.