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evablogger [386]
3 years ago
7

7. A pool cue ball moving at 2.1 m/s east collides in a straight line with the eight ball at rest. Find the velocity of the eigh

t ball after the collision if momentum is conserved and
A. the cue ball stops. (5 points)
B. the cue ball continues on in the same direction at 0.10 m/s. (5 points)
C. the cue ball continues on in the same direction at 0.70 m/s. (5 points)
Physics
2 answers:
Hitman42 [59]3 years ago
8 0

the answer is letter B


MArishka [77]3 years ago
6 0
I think the answer is C the cue ball con....
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Anions have more electrons than protons and so have a net negative charge. Cations have more protons than electrons and so have a net positive charge. Zwitterions are neutral and have both positive and negative charges at different locations throughout the molecule.

Explanation:

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Calculate the standard electrode potential difference (e°) of the daniell cell (at 1 bar) if temperature is 473.15 k.
anzhelika [568]
Missing data in the text of the exercise: The molar concentration of Zinc is 10 times the molar concentration of copper.

Solution:

1) First of all, let's calculate the standard electrode potential difference at standard temperature. This is given by:
E^0=E_{cat}^0-E_{an}^0
where E_{cat}^0 is the standard potential at the cathode, while E_{an}^0 is the standard potential at the anode. For a Daniel Cell, at the cathode we have copper: E_{Cu}^0=+0.34 V, while at the anode we have zinc: E_{Zn}^0=-0.76 V. Therefore, at standard temperature the electrode potential difference of the Daniel Cell is
E^0=+0.34 V-(-0.76 V)=+1.1 V

2) To calculate E^0 at any temperature T, we should use Nerst equation:
E^0(T)=E^0- \frac{R T}{z F} \ln  \frac{[Zn]}{[Cu]}
where 
R=8.31 J/(K mol)
T=473.15 K is the temperature in our problem
z=2 is the number of electrons transferred in the cell's reaction
F=9.65\cdot 10^4 C/mol is the Faraday's constant
[Zn] and [Cu] are the molar concentrations of zinc and in copper, and in our problem we have [Zn]=10[Cu].
Using all these data inside the equation, and using E^0=+1.1 V, in the end we find:
E^0(T)=E^0- \frac{R T}{z F} \ln \frac{[Zn]}{[Cu]}=+1.053 V
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3 years ago
A zero on the kelvin temperature scale is called “absolute zero.” <br> a. true <br> b. false
ryzh [129]
True.
A zero on the Kelvin temperature scale is also know as Absolute Zero because that is when the atom(s) have literally no kinetic energy.
8 0
3 years ago
Read 2 more answers
Uranium has two naturally occurring isotopes. 238u has a natural abundance of 99.3% and 235u has an abundance of 0.7%. it is the
dmitriy555 [2]

The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.

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6 0
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